Here's the question you clicked on:
swissgirl
Reduce the polynomial and find its complex roots \(f(x)=x^4+5x^3-9x^2-85x-136\)
lol didnt know u were on
not quite sure how to reduce it since u start dealing with decimals. It shld be quite simple though
By reduce do you mean factor?
Well, I have a couple ideas, so let's see if I can do this by hand... \[f(x)=x^4+5x^3-9x^2-85x-136\\ f(x)=x^4-17x^2+5x^3+8x^2-17(5x-8)\\ f(x)=x^4-17x^2+x^2(5x+8)-17(5x+8)\\ f(x)=x^4-17x^2+(x^2-17)(5x+8)\\ f(x)=x^2(x^2-17)+(x^2-17)(5x+8)\\ f(x)=(x^2-17)(x^2+5x+8) \]
So you can use the quadratic formula on \(x^2+5x+8\) to find the complex roots, and just \[x^2-17=0\implies x=\pm\sqrt{17}\]For the real roots.
Let me just see if I can follow what u did
Take your time. I'm honestly very surprised I was able to factor that almost entirely by hand. (I used wolfram to check correctness, and to find the gcd of 85, 136).
idk if its possible. Dont drive urself crazy buttt I cant decipher what is squred and what is tripled. Is it possible to make it larger
\[\Large f(x)=x^4+5x^3-9x^2-85x-136\\ \Large f(x)=x^4-17x^2+5x^3+8x^2-17(5x-8)\\ \Large f(x)=x^4-17x^2+x^2(5x+8)-17(5x+8)\\ \Large f(x)=x^4-17x^2+(x^2-17)(5x+8)\\ \Large f(x)=x^2(x^2-17)+(x^2-17)(5x+8)\\ \Large f(x)=(x^2-17)(x^2+5x+8)\]
OKKKK so like will this method always work?
Not always. This is just factoring by grouping, and while potentially useful, it is often difficult to identify the correct time to use it, and what to group together. I just got lucky that I guessed the right things to group. For example, if I had \[\Large f(x)=x^4+5x^3-10x^2-85x-136\]instead, I would not be able to group it as easily.
ohhhh i seee. I guesss I have to play around. Not as simple as I wish it wld be. Thanks KG:)))))))))))
You're welcome. I will note however, that if they tell you to factor something, it's usually possible to do it by hand with a little cleverness.
Haha So I hope and pray that it will be so. lol Thanks KGGGG