A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
can someone help my find the limit if x>0 sinx/ cubed root of x
anonymous
 3 years ago
can someone help my find the limit if x>0 sinx/ cubed root of x

This Question is Closed

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1multiply and divide by x , to get the function in the form of sin x/ x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can u draw it out so i can see what ur talking about

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\huge\frac{sin x}{x}\:\frac{x}{\sqrt[3]{x}}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and then from there which method would u use

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1u know the formula : \[\lim_{x \rightarrow 0}\: sinx / x = 1\] ? use that for first fraction.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh ok! omg now it makes sense thank you @hartnn

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1welcome :) what did u get the final answer as ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i need help again actually with number 84 now

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1ok, if f(x) = root x what will be f(x+h) ?? u know?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im confused on tht part

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1ok, to get f(x+h) just replace x by (x+h) in f(x) so f(x+h) will be \(\sqrt{x+h}\) ok?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1i m using h instead of delta x just for convenience here. so now u put that in {f(x+h)f(x) }/ h to get \(\frac{\sqrt{x+h}\sqrt{h}}{h}\) got this ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1now mutiply and divide by \(\sqrt{x+h}+\sqrt{h}\) and use (a+b)(ab) = a^2  b^2 and tell me what u get in numerator ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh so ur multiplying it by its conjugate right ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yup, so that i get only h in numerator and that i can cancel it with h in denominator ok?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1i made a typo ..... it should be \(\sqrt{x} \) and not \(\sqrt{h} \) in the numerator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait a minute now im confused a bit

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1because itsf(x+h)  f(x) which is \(\sqrt{x+h} \) \(\sqrt{x} \)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so now now mutiply and divide by \(\sqrt{x+h}+\sqrt{x}\) and use (a+b)(ab) = a^2  b^2 and tell me what u get in numerator ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0would it still be h in the numerator i think..

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yup, because (x+h) x = x+hx = h this h cancels out with h in denominator and u have only 1 in numerator, right ? and what u have in denominator now?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you have \[\sqrt{x+h} + \sqrt{x}\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yes, u are right, be confident :) now just put h =0 because lim h> 0 and tell me what u get in denominator after putting h=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x+0} +\sqrt{x}\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yup, thats your denominator = \(2\sqrt{x}\) and then your final answer would be \(\huge\frac{1}{2\sqrt{x}}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hang on im confused how do u get \[\frac{ 1 }{ 2\sqrt{x} }\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\sqrt{x+0} +\sqrt{x}=\sqrt{x} +\sqrt{x}=2\sqrt{x}\) and there was 1 in the numerator, previously, right ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u r a very helpful math teacher!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.