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SugarRainbow
find sec and csc when tan=3?
if tan = 3 then that means opposite side is 3 and adjacent side is 1. make sense?
i think so it's one because on the unit circle the radius is one i guess? that's how i'm thinking about it
no.. that's actually because \[\tan = 3 = \frac 31 = \frac{opposite}{adjacent}\] so opposite side is 3 and adjacent side is 1
does it make sense now?
yeah okay that makes more sense
good so that means hypotenuse is \[\huge \sqrt{3^2 + 1^2}\implies \sqrt{9 + 1} \implies \sqrt {10}\] right?
yeah that makes comeplete sense! okay so in another question i have to find tan and cot when sec=4 so does that mean....
\[\sec = 4 = \frac 41 = \frac{hypotenuse}{adjacent}\] so that means hypotenuse = 4 and adjacent = 1 right?
the hypotenuse is 4 and the adjacent angle is 1?|dw:1347253071421:dw|
now....use pythagorean theorem \[\huge a^2 + b^2 = c^2\] \[\huge \implies a^2 = c^2 - b^2\] \[\huge \implies a = \sqrt{c^2 - b^2}\] got it?
yeah okay i think i getting this! okay last thing, what if i get something wierd like cos=0.8?
you turn them into fractions
okay so whenever i get a number i think of that number over what gives me that right?
hmm many word plays but it sounds about right
okay cool thank you so much!