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SugarRainbow

  • 3 years ago

find sec and csc when tan=3?

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  1. lgbasallote
    • 3 years ago
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    if tan = 3 then that means opposite side is 3 and adjacent side is 1. make sense?

  2. SugarRainbow
    • 3 years ago
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    i think so it's one because on the unit circle the radius is one i guess? that's how i'm thinking about it

  3. lgbasallote
    • 3 years ago
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    no.. that's actually because \[\tan = 3 = \frac 31 = \frac{opposite}{adjacent}\] so opposite side is 3 and adjacent side is 1

  4. lgbasallote
    • 3 years ago
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    does it make sense now?

  5. SugarRainbow
    • 3 years ago
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    yeah okay that makes more sense

  6. lgbasallote
    • 3 years ago
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    good so that means hypotenuse is \[\huge \sqrt{3^2 + 1^2}\implies \sqrt{9 + 1} \implies \sqrt {10}\] right?

  7. SugarRainbow
    • 3 years ago
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    yeah that makes comeplete sense! okay so in another question i have to find tan and cot when sec=4 so does that mean....

  8. lgbasallote
    • 3 years ago
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    \[\sec = 4 = \frac 41 = \frac{hypotenuse}{adjacent}\] so that means hypotenuse = 4 and adjacent = 1 right?

  9. SugarRainbow
    • 3 years ago
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    the hypotenuse is 4 and the adjacent angle is 1?|dw:1347253071421:dw|

  10. lgbasallote
    • 3 years ago
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    now....use pythagorean theorem \[\huge a^2 + b^2 = c^2\] \[\huge \implies a^2 = c^2 - b^2\] \[\huge \implies a = \sqrt{c^2 - b^2}\] got it?

  11. SugarRainbow
    • 3 years ago
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    yeah okay i think i getting this! okay last thing, what if i get something wierd like cos=0.8?

  12. lgbasallote
    • 3 years ago
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    0.8 means 8/10

  13. lgbasallote
    • 3 years ago
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    you turn them into fractions

  14. SugarRainbow
    • 3 years ago
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    okay so whenever i get a number i think of that number over what gives me that right?

  15. lgbasallote
    • 3 years ago
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    hmm many word plays but it sounds about right

  16. SugarRainbow
    • 3 years ago
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    okay cool thank you so much!

  17. lgbasallote
    • 3 years ago
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    welcome

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