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ragman
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find inverse laplace transform of F(s)= (s^2+2s+5/(s^2(s+1))
 one year ago
 one year ago
ragman Group Title
find inverse laplace transform of F(s)= (s^2+2s+5/(s^2(s+1))
 one year ago
 one year ago

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ragman Group TitleBest ResponseYou've already chosen the best response.0
'note' sorry this is my first time using this what do you mean by that?
 one year ago

Skaematik Group TitleBest ResponseYou've already chosen the best response.0
Im just bookmarking this question so that I can return to it later. :D Id want to know the answer too
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
oh ok sounds good thanks
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
your question is \[\huge \mathcal L ^{1} \left \{ s^2 + 2s + \frac 5{s^2(s+1)}\right \}\]
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
@ragman you there?
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
hey sorry about the late reply but my question is actually (s^2+22+5) / (s^2(s+1) sorry i forgot the other )
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
@lgbasallote
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
uhh s^2 + 22 + 5??
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
dang i keep doing typos 2s not 22 so yeah its (s^2+2s+5)
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
so.. \[\huge \mathcal L ^{1} \left \{ \frac{s^2 + 2s + 5}{s^2(s+1)} \right \}\]
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
yup perfect
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
can u do partial fractions ??
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
@hartnn yeah thats what i was doing but for some reason i could figure out the other two variable maybe im solving it incorrectly but i got 3 for A and 5 for B
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
where's C?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
those are correct, so u need only C right ? where u took C above s+1
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
your P.F. should be \[\huge \frac As + \frac B{s^2} + \frac C{s+1}\]
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
so you have \[\implies As(s+1) + B(s+1) + Cs^2 = s^2 + 2s + 5\]
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
oh ok so thats where i messed up i thought that where C is it should be (Cs+D) so i was trying to solve for both of those variables
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
nopes only C, if it were s^2+1 u would have taken Cx+D
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
so i think u can get C now, right?
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
oh i see now and yeah i believe i can get C now trying it right now
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
i think it will change your A value too
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
so you best check
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
great tell us what u get C as....we all will verify that. A is correct.
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
nope nevermind..it stays the same
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
ok sounds good got B=5 finding A now
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
A=3 and C=4 is that what you guys got?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
yup, same.Good work.
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
A =3?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
yeah that's right
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
ok cool i was about to write out how i got it lol
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
everything's right
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
and now i just plug back all the variables right
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
yup, and use inverse laplace formulas.
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
yep find \[\huge \mathcal L ^{1} \left \{ \frac 3s + \frac 5s + \frac 4{s+1} \right \}\]
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
uhh that should be 5/s^2
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
ok sorry im just learning this but how do you go about doing that im trying to find the L^1 formula but my notes arent really helping
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
here's a hint: \[\huge \mathcal L \{ a \} = \frac as\] \[\huge \mathcal L \{ t^n\} = \frac{n!}{s^{n+1}}\] \[\huge \mathcal L \{e^{at} \} = \frac{a}{s a}\] does that help?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
uhhh wait... wrong formula for last one
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
\[\huge \mathcal L \{e^{at} \} = \frac{1}{sa}\] better
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
yes thats very helpful but im getting confused with what n should be in the middle equations
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
n is the exponent
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
so it would be 2?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
for example: \[\huge \mathcal L \{ t^2 \} = \frac{2!}{s^{2+1}} \implies \frac{2}{s^3}\]
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
thats whats a lil confusing to me because on the denominator it would have to be n=1 so that it would equal s^2 but on the numerator 1! equals 1 right ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
yes thats true, so u will have 5t^1= 5t ....isn't it ? u can verify that u should get final answer as 5t3+4e^(t) did u get that?
 one year ago

ragman Group TitleBest ResponseYou've already chosen the best response.0
yup thats what i got thanks
 one year ago
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