A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
NOT A QUESTION (JUST INTERESTING)
Alternate derivation of the quadratic formula
anonymous
 4 years ago
NOT A QUESTION (JUST INTERESTING) Alternate derivation of the quadratic formula

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You may be familiar with the derivation of the quadratic formula by completing the square...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0We can get the exact same result by using the sum and products of roots

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0given a quadratic equation: ax^2+bx+c=0 let the two roots be p and q (which are equal to x)

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1yup, tried that, much interesting ...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What if we found pq? (pq)^2 = p^2  2pq + q^2 = (p^2 + q^2)  2pq = (p+q)^2  2pq  2pq = (p+q)^2  4pq = b^2/a^2  4*c/a = (b^24ac)/a^2 therefore pq = √(b^24ac) /a

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1did the same way, good,go on.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(p+q)+(pq)=2p=2x (because a root is a solution of x) 2x = b/a + √(b^24ac) /a x = b±√(b^24ac)  2a

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And viola, the quadratic formula

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.0Excellent ! somehow ive never seen this before. thank you !!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0not satisfied with the completing the square solution huh?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nah, long at messy.. this way seems so much more elegant
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.