A community for students.
Here's the question you clicked on:
 0 viewing
mazehaq
 4 years ago
3(x3)^1/3  4(x3)^4/3 + (x3)^7/3 = 0
To make it easier, I substituted (x3) with x, in which I got x^1/3(3  4x +x^2) ...but it can't be factored. Help me out! It's a fairly easy question I bet, but I need a nice way of solving it. Thank you! :)
mazehaq
 4 years ago
3(x3)^1/3  4(x3)^4/3 + (x3)^7/3 = 0 To make it easier, I substituted (x3) with x, in which I got x^1/3(3  4x +x^2) ...but it can't be factored. Help me out! It's a fairly easy question I bet, but I need a nice way of solving it. Thank you! :)

This Question is Closed

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1actually you might want to substitute x  3 with a instead to avoid confusion

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1but you're right anyway... except for the last part

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1wait on second thought you're right

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1and it can be factored... \[\huge a^{\frac 13} (3  4a + a^2) \implies a^{\frac 13} (a^2  4a + 3)\] can you see it now?

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1a^2  4a + 3 is factorable

mazehaq
 4 years ago
Best ResponseYou've already chosen the best response.1Oh okay! I kept thinking that it was a^2 + 4a  3

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1yeah. that one isn't factorable

mazehaq
 4 years ago
Best ResponseYou've already chosen the best response.1so 3  4a + a^2 is a^2  4a + 3 ...right?

mazehaq
 4 years ago
Best ResponseYou've already chosen the best response.1So wait, how would I figure out the final answer, I am at (x3)^1/3 (x7)(x7)=0

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1they shouldn't be equal...

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1how did you factor a^2  4a + 3?

mazehaq
 4 years ago
Best ResponseYou've already chosen the best response.1I skipped a few steps. Remember a = (x3) a^1/3 (a1)(a3) = 0 (x3)^1/3 [(x31)(x33)] = 0 (x3)^1/3 (x4)(x6) = 0

mazehaq
 4 years ago
Best ResponseYou've already chosen the best response.1sorry about my previous comment tho, I totally typed it wrong, my computer is lagging so bad.

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1right. that's better

mazehaq
 4 years ago
Best ResponseYou've already chosen the best response.1So how do I solve the end?

mazehaq
 4 years ago
Best ResponseYou've already chosen the best response.1(x3)^1/3 (x4)(x6) = 0

mazehaq
 4 years ago
Best ResponseYou've already chosen the best response.1don't I make each = to zero

mazehaq
 4 years ago
Best ResponseYou've already chosen the best response.1Like, 2 of my answers will be 4 & 6...

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1now..just equate (x3)^1/3 to 0

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1\[(x  3)^{\frac 13} = 0\]

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1take the cube root of both sides..what happens?

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1so there's your answer

mazehaq
 4 years ago
Best ResponseYou've already chosen the best response.1Okay, so answer is 3,4,6 :) thanks!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.