Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Mello

  • 2 years ago

Simplify the following

  • This Question is Closed
  1. Mello
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1347334599772:dw|

  2. CliffSedge
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    There isn't much you can do with that. You can try factoring. There's a difference of cubes up top, and the bottom is a square of sorts.

  3. Mello
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @CliffSedge I know that the answer should be 2013. I have no idea how to get there though

  4. CliffSedge
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Just to make sure we're looking at the same thing, is this what you wrote? \[\frac{8-27^n}{4+2 \cdot 3^n +9} \space +2011+3^n\]

  5. Mello
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yup

  6. CliffSedge
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Well if the answer is 2013, then \[\frac{8-27^n}{4+2 \cdot 3^n +9} +3^n = 2.\]

  7. Mello
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Is it possible to add 2^2 to 2?

  8. CliffSedge
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The top can be factored as a difference of cubes: \[8-27^n = 2^3-3^{3n} = (2-3^n)(4+2 \cdot 3^n+3^{2n})\]

  9. CliffSedge
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What do you mean, "add 2^2 to 2?" 2^2 = 4, 4+2=6.

  10. CliffSedge
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Are you sure that denominator isn't 4+2*3^n+9^n ?

  11. CliffSedge
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Then it would work out just fine.

  12. Mello
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @CliffSedge Im sure, its just 9.

  13. CliffSedge
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\frac{8-27^n}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[\frac{2^3-3^{3n}}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[\frac{(2-3^n)((4+2 \cdot 3^n +9^n)}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[2-3^n +2011+3^n =2013.\]

  14. CliffSedge
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Well, that's unfortunate.

  15. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.