Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Simplify the following

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

|dw:1347334599772:dw|
There isn't much you can do with that. You can try factoring. There's a difference of cubes up top, and the bottom is a square of sorts.
@CliffSedge I know that the answer should be 2013. I have no idea how to get there though

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Just to make sure we're looking at the same thing, is this what you wrote? \[\frac{8-27^n}{4+2 \cdot 3^n +9} \space +2011+3^n\]
yup
Well if the answer is 2013, then \[\frac{8-27^n}{4+2 \cdot 3^n +9} +3^n = 2.\]
Is it possible to add 2^2 to 2?
The top can be factored as a difference of cubes: \[8-27^n = 2^3-3^{3n} = (2-3^n)(4+2 \cdot 3^n+3^{2n})\]
What do you mean, "add 2^2 to 2?" 2^2 = 4, 4+2=6.
Are you sure that denominator isn't 4+2*3^n+9^n ?
Then it would work out just fine.
@CliffSedge Im sure, its just 9.
\[\frac{8-27^n}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[\frac{2^3-3^{3n}}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[\frac{(2-3^n)((4+2 \cdot 3^n +9^n)}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[2-3^n +2011+3^n =2013.\]
Well, that's unfortunate.

Not the answer you are looking for?

Search for more explanations.

Ask your own question