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CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0There isn't much you can do with that. You can try factoring. There's a difference of cubes up top, and the bottom is a square of sorts.

Mello
 2 years ago
Best ResponseYou've already chosen the best response.0@CliffSedge I know that the answer should be 2013. I have no idea how to get there though

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Just to make sure we're looking at the same thing, is this what you wrote? \[\frac{827^n}{4+2 \cdot 3^n +9} \space +2011+3^n\]

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Well if the answer is 2013, then \[\frac{827^n}{4+2 \cdot 3^n +9} +3^n = 2.\]

Mello
 2 years ago
Best ResponseYou've already chosen the best response.0Is it possible to add 2^2 to 2?

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0The top can be factored as a difference of cubes: \[827^n = 2^33^{3n} = (23^n)(4+2 \cdot 3^n+3^{2n})\]

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0What do you mean, "add 2^2 to 2?" 2^2 = 4, 4+2=6.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Are you sure that denominator isn't 4+2*3^n+9^n ?

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Then it would work out just fine.

Mello
 2 years ago
Best ResponseYou've already chosen the best response.0@CliffSedge Im sure, its just 9.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{827^n}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[\frac{2^33^{3n}}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[\frac{(23^n)((4+2 \cdot 3^n +9^n)}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[23^n +2011+3^n =2013.\]

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Well, that's unfortunate.
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