A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Simplify the following
anonymous
 4 years ago
Simplify the following

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1347334599772:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There isn't much you can do with that. You can try factoring. There's a difference of cubes up top, and the bottom is a square of sorts.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@CliffSedge I know that the answer should be 2013. I have no idea how to get there though

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just to make sure we're looking at the same thing, is this what you wrote? \[\frac{827^n}{4+2 \cdot 3^n +9} \space +2011+3^n\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well if the answer is 2013, then \[\frac{827^n}{4+2 \cdot 3^n +9} +3^n = 2.\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is it possible to add 2^2 to 2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The top can be factored as a difference of cubes: \[827^n = 2^33^{3n} = (23^n)(4+2 \cdot 3^n+3^{2n})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What do you mean, "add 2^2 to 2?" 2^2 = 4, 4+2=6.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Are you sure that denominator isn't 4+2*3^n+9^n ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Then it would work out just fine.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@CliffSedge Im sure, its just 9.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{827^n}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[\frac{2^33^{3n}}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[\frac{(23^n)((4+2 \cdot 3^n +9^n)}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[23^n +2011+3^n =2013.\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, that's unfortunate.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.