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CliffSedgeBest ResponseYou've already chosen the best response.0
There isn't much you can do with that. You can try factoring. There's a difference of cubes up top, and the bottom is a square of sorts.
 one year ago

MelloBest ResponseYou've already chosen the best response.0
@CliffSedge I know that the answer should be 2013. I have no idea how to get there though
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
Just to make sure we're looking at the same thing, is this what you wrote? \[\frac{827^n}{4+2 \cdot 3^n +9} \space +2011+3^n\]
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
Well if the answer is 2013, then \[\frac{827^n}{4+2 \cdot 3^n +9} +3^n = 2.\]
 one year ago

MelloBest ResponseYou've already chosen the best response.0
Is it possible to add 2^2 to 2?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
The top can be factored as a difference of cubes: \[827^n = 2^33^{3n} = (23^n)(4+2 \cdot 3^n+3^{2n})\]
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
What do you mean, "add 2^2 to 2?" 2^2 = 4, 4+2=6.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
Are you sure that denominator isn't 4+2*3^n+9^n ?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
Then it would work out just fine.
 one year ago

MelloBest ResponseYou've already chosen the best response.0
@CliffSedge Im sure, its just 9.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
\[\frac{827^n}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[\frac{2^33^{3n}}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[\frac{(23^n)((4+2 \cdot 3^n +9^n)}{4+2 \cdot 3^n +9^n} \space +2011+3^n \rightarrow\] \[23^n +2011+3^n =2013.\]
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
Well, that's unfortunate.
 one year ago
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