vivalakoda
Which inequality is graphed?
y > |x + 4| – 2
y < |x – 4| – 2
y > |x + 4| + 2
y < |x – 4| + 2
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vivalakoda
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andriod09
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what is the rule about inequality? do you know it?
vivalakoda
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No.
andriod09
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okay,
Rule #1: Inequalities that are grater than or equal to, shade up,
Rule #2: Inequalities that are less than or equal to shade down.
Have you solved any of the equations?
vivalakoda
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I don't know how :c
andriod09
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How come you have these problems than?
vivalakoda
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I do online school. So they just give me random questions
andriod09
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ahh, so your homeschooled?
vivalakoda
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Unfortunately!
andriod09
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There is nothing wrong with being homeschooled, except maybe your social life. :] im homwschooled too. lol. anyy wayyy.
vivalakoda
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Ohhhhhhh. Well I'm not used to it! Lol. I just started this year, it's my like second week. I went to public school all my life so it's a big adjustment.
andriod09
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same here
I am doing the Life of Fred math series, you should try it. :].
andriod09
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ok, do you know about absolute values?
vivalakoda
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Yes
andriod09
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So then make then abosolutes and solve.
vivalakoda
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Whaaaaaaaaaaaaaaaaaaat
Confused
andriod09
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absolute value = |x+4|
vivalakoda
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I think I figured it out, I had to set the absolute value to equal zero in which I found the vertex, which is 2, 4
andriod09
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but when you absolute the vaule, it becomes a positive number, and 0 is neither positive nor negative, :/
vivalakoda
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That's what my teacher told me to do D:
vivalakoda
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Wtf
jim_thompson5910
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The vertex of that given graph is (4,2)
jim_thompson5910
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The vertex of y = a|x-h| + k is (h,k)
andriod09
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jim, im a freshman, in honours algebra, and that makes no sense. lol
vivalakoda
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Algebra 1?
jim_thompson5910
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y = a|x-h| + k is the general form of an absolute value equation
jim_thompson5910
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And the vertex is (h,k)
jim_thompson5910
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Ex:
y = a|x-h| + k
Let a = 2, h = 3 and k = 5 to get
y = 2|x-3|+5
The vertex of y = 2|x-3|+5 is (3,5)