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experimentX
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Let \( a, b, c > 0 \), show that
\[ \sqrt{\frac{11a}{5a+6b}}+\sqrt{\frac{11b}{5b+6c}}+\sqrt{\frac{11c}{5c+6a}} \leq 3. \]
from http://math.stackexchange.com/questions/193568/inequalitysqrtfrac11a5a6bsqrtfrac11b5b6csqrtfrac11c
 2 years ago
 2 years ago
experimentX Group Title
Let \( a, b, c > 0 \), show that \[ \sqrt{\frac{11a}{5a+6b}}+\sqrt{\frac{11b}{5b+6c}}+\sqrt{\frac{11c}{5c+6a}} \leq 3. \] from http://math.stackexchange.com/questions/193568/inequalitysqrtfrac11a5a6bsqrtfrac11b5b6csqrtfrac11c
 2 years ago
 2 years ago

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TuringTest Group TitleBest ResponseYou've already chosen the best response.1
yeah this is gonna be a pain with LaTeX down :S
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
isn't latex working for you? this Q seems fairly complicated ... I've been stalking for more than 2 hrs.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
no, GoDaddy isn't supporting mathjax right now, there is an announcement in the yellow bar on the home page, Why, is it working for you o.O ?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
I'm using chrome ... what server does MathJax uses to parse latex?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
not sure, not that tech savvy... but I have chrome as well. do you see the TeX normally or not?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
I see it normally ...
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Let us suppose a is the largest number out of the the three...... then dw:1347343904345:dw will have the largest value.... So now, this value is maximum when a approaches infinity So,dw:1347343979969:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
If a approaches infinity then surely dw:1347344106656:dw will be zero
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
And the term dw:1347344150915:dw also cannot be greater than 1.48
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
right?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
as a, or b, or c approaches infinity
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
It will be undefined
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
The maximum value is when a=b=c
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
let a>=b>=c.. now 11a / 5a + 6b = 11/ 5 + 6(b/a) > whole term always less than or equal toone since b>=a thus sqrt (of this) <= 1 for 11b/5b + 6c = 11/5 + 6(c/b) > same thing 11c/5c + 6a = 11(c/a) /5(c/a) + 6 let c/a = m => 11m / 5m + 6 = 11/5 ( m / m + 6/5) = 2.2 ( m + 6/5  6/5) /(m+6/5) =2.2 ( 1  1.2/(m+1.2) ) note that m>=1 for m tends to infinity , max value becomes 2.2 and sqrt(2.2) is approx 1.4 something.. other 2 terms were less than 1 and this one's maxima is 1.4 something,, hence there sum is always less than 3..and equality holds as a=b=c..
 2 years ago
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