anonymous
  • anonymous
How do I solve this problem -7(the lesser than or equal to sign) 2x+3(<) 5
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
you are going to need to set up two equations
anonymous
  • anonymous
one -7(less than or equal sign) 2X+3 two 2X+3(<)5 you will get two answers it would look like this for example 69
anonymous
  • anonymous
Alright Thank you, I will tell you what I came up with so far

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
k
anonymous
  • anonymous
for my solutions I have(-5,infinity symbol] and (5/2,infinity symbol)
anonymous
  • anonymous
Infinity?
anonymous
  • anonymous
ok lets work Equation one -7(Less than or equal) 2X+3
anonymous
  • anonymous
subtract 3 from both sides
anonymous
  • anonymous
I end up with 2 is less than or equla to x
anonymous
  • anonymous
you should get -10 since you subtracted -3 and you have a -7 on the other side you get -10
anonymous
  • anonymous
alright
anonymous
  • anonymous
-7 (less than equal) 2X+3 -3 -3 =-10 (less than equal) 2x
anonymous
  • anonymous
then divide by 2 and we get -5
anonymous
  • anonymous
yup good job!
anonymous
  • anonymous
do the same for the other equation
anonymous
  • anonymous
but I am supposed to express each in interval notation
anonymous
  • anonymous
and for the other equation x<5/2
anonymous
  • anonymous
you should get 1 for the other equation
anonymous
  • anonymous
2X+3<5 -3<-3 2X<2 divide by 2 on both side 2 2 X=1
anonymous
  • anonymous
|dw:1347312457904:dw|
anonymous
  • anonymous
your interval notation sould look something like this its a bad drawing, and than draw the arrows (left or right)
anonymous
  • anonymous
The solution would then look x<1 for the other one
phi
  • phi
if you started with -7 ≤ 2x+3 < 5 you should get, after simplifying, -5 ≤ x < 1 in interval notation, this is [-5,1) the square brackets indicates -5 is part of the interval. ) means the upper value is a limit, approached but not reached.
anonymous
  • anonymous
Alright, thank you

Looking for something else?

Not the answer you are looking for? Search for more explanations.