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you are going to need to set up two equations
one -7(less than or equal sign) 2X+3 two 2X+3(<)5 you will get two answers it would look like this for example 6
Alright Thank you, I will tell you what I came up with so far
for my solutions I have(-5,infinity symbol] and (5/2,infinity symbol)
ok lets work Equation one -7(Less than or equal) 2X+3
subtract 3 from both sides
I end up with 2 is less than or equla to x
you should get -10 since you subtracted -3 and you have a -7 on the other side you get -10
-7 (less than equal) 2X+3 -3 -3 =-10 (less than equal) 2x
then divide by 2 and we get -5
yup good job!
do the same for the other equation
but I am supposed to express each in interval notation
and for the other equation x<5/2
you should get 1 for the other equation
2X+3<5 -3<-3 2X<2 divide by 2 on both side 2 2 X=1
your interval notation sould look something like this its a bad drawing, and than draw the arrows (left or right)
The solution would then look x<1 for the other one
if you started with -7 ≤ 2x+3 < 5 you should get, after simplifying, -5 ≤ x < 1 in interval notation, this is [-5,1) the square brackets indicates -5 is part of the interval. ) means the upper value is a limit, approached but not reached.
Alright, thank you