## Tombrokaw 3 years ago How do I solve this problem -7(the lesser than or equal to sign) 2x+3(<) 5

1. gangescom

you are going to need to set up two equations

2. gangescom

one -7(less than or equal sign) 2X+3 two 2X+3(<)5 you will get two answers it would look like this for example 6<x>9

3. Tombrokaw

Alright Thank you, I will tell you what I came up with so far

4. gangescom

k

5. Tombrokaw

for my solutions I have(-5,infinity symbol] and (5/2,infinity symbol)

6. gangescom

Infinity?

7. gangescom

ok lets work Equation one -7(Less than or equal) 2X+3

8. gangescom

subtract 3 from both sides

9. Tombrokaw

I end up with 2 is less than or equla to x

10. gangescom

you should get -10 since you subtracted -3 and you have a -7 on the other side you get -10

11. Tombrokaw

alright

12. gangescom

-7 (less than equal) 2X+3 -3 -3 =-10 (less than equal) 2x

13. Tombrokaw

then divide by 2 and we get -5

14. gangescom

yup good job!

15. gangescom

do the same for the other equation

16. Tombrokaw

but I am supposed to express each in interval notation

17. Tombrokaw

and for the other equation x<5/2

18. gangescom

you should get 1 for the other equation

19. gangescom

2X+3<5 -3<-3 2X<2 divide by 2 on both side 2 2 X=1

20. gangescom

|dw:1347312457904:dw|

21. gangescom

your interval notation sould look something like this its a bad drawing, and than draw the arrows (left or right)

22. Tombrokaw

The solution would then look x<1 for the other one

23. phi

if you started with -7 ≤ 2x+3 < 5 you should get, after simplifying, -5 ≤ x < 1 in interval notation, this is [-5,1) the square brackets indicates -5 is part of the interval. ) means the upper value is a limit, approached but not reached.

24. Tombrokaw

Alright, thank you