A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
How do I solve this problem 7(the lesser than or equal to sign) 2x+3(<) 5
anonymous
 4 years ago
How do I solve this problem 7(the lesser than or equal to sign) 2x+3(<) 5

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you are going to need to set up two equations

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0one 7(less than or equal sign) 2X+3 two 2X+3(<)5 you will get two answers it would look like this for example 6<x>9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Alright Thank you, I will tell you what I came up with so far

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for my solutions I have(5,infinity symbol] and (5/2,infinity symbol)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok lets work Equation one 7(Less than or equal) 2X+3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0subtract 3 from both sides

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I end up with 2 is less than or equla to x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you should get 10 since you subtracted 3 and you have a 7 on the other side you get 10

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.07 (less than equal) 2X+3 3 3 =10 (less than equal) 2x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then divide by 2 and we get 5

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do the same for the other equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but I am supposed to express each in interval notation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and for the other equation x<5/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you should get 1 for the other equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02X+3<5 3<3 2X<2 divide by 2 on both side 2 2 X=1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1347312457904:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your interval notation sould look something like this its a bad drawing, and than draw the arrows (left or right)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The solution would then look x<1 for the other one

phi
 4 years ago
Best ResponseYou've already chosen the best response.1if you started with 7 ≤ 2x+3 < 5 you should get, after simplifying, 5 ≤ x < 1 in interval notation, this is [5,1) the square brackets indicates 5 is part of the interval. ) means the upper value is a limit, approached but not reached.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.