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you are going to need to set up two equations

Alright Thank you, I will tell you what I came up with so far

for my solutions I have(-5,infinity symbol] and (5/2,infinity symbol)

Infinity?

ok lets work Equation one
-7(Less than or equal) 2X+3

subtract 3 from both sides

I end up with 2 is less than or equla to x

you should get -10
since you subtracted -3 and you have a -7 on the other side you get -10

alright

-7 (less than equal) 2X+3
-3 -3
=-10 (less than equal) 2x

then divide by 2
and we get -5

yup good job!

do the same for the other equation

but I am supposed to express each in interval notation

and for the other equation x<5/2

you should get 1 for the other equation

2X+3<5
-3<-3
2X<2 divide by 2 on both side
2 2
X=1

|dw:1347312457904:dw|

The solution would then look x<1
for the other one

Alright, thank you