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anonymous
 3 years ago
How do I solve this problem 7(the lesser than or equal to sign) 2x+3(<) 5
anonymous
 3 years ago
How do I solve this problem 7(the lesser than or equal to sign) 2x+3(<) 5

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you are going to need to set up two equations

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0one 7(less than or equal sign) 2X+3 two 2X+3(<)5 you will get two answers it would look like this for example 6<x>9

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Alright Thank you, I will tell you what I came up with so far

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for my solutions I have(5,infinity symbol] and (5/2,infinity symbol)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok lets work Equation one 7(Less than or equal) 2X+3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0subtract 3 from both sides

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I end up with 2 is less than or equla to x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you should get 10 since you subtracted 3 and you have a 7 on the other side you get 10

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.07 (less than equal) 2X+3 3 3 =10 (less than equal) 2x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then divide by 2 and we get 5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do the same for the other equation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but I am supposed to express each in interval notation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and for the other equation x<5/2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you should get 1 for the other equation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.02X+3<5 3<3 2X<2 divide by 2 on both side 2 2 X=1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1347312457904:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0your interval notation sould look something like this its a bad drawing, and than draw the arrows (left or right)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The solution would then look x<1 for the other one

phi
 3 years ago
Best ResponseYou've already chosen the best response.1if you started with 7 ≤ 2x+3 < 5 you should get, after simplifying, 5 ≤ x < 1 in interval notation, this is [5,1) the square brackets indicates 5 is part of the interval. ) means the upper value is a limit, approached but not reached.
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