Tombrokaw
How do I solve this problem -7(the lesser than or equal to sign) 2x+3(<) 5
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gangescom
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you are going to need to set up two equations
gangescom
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one
-7(less than or equal sign) 2X+3
two
2X+3(<)5
you will get two answers
it would look like this
for example
6<x>9
Tombrokaw
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Alright Thank you, I will tell you what I came up with so far
gangescom
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k
Tombrokaw
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for my solutions I have(-5,infinity symbol] and (5/2,infinity symbol)
gangescom
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Infinity?
gangescom
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ok lets work Equation one
-7(Less than or equal) 2X+3
gangescom
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subtract 3 from both sides
Tombrokaw
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I end up with 2 is less than or equla to x
gangescom
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you should get -10
since you subtracted -3 and you have a -7 on the other side you get -10
Tombrokaw
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alright
gangescom
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-7 (less than equal) 2X+3
-3 -3
=-10 (less than equal) 2x
Tombrokaw
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then divide by 2
and we get -5
gangescom
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yup good job!
gangescom
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do the same for the other equation
Tombrokaw
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but I am supposed to express each in interval notation
Tombrokaw
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and for the other equation x<5/2
gangescom
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you should get 1 for the other equation
gangescom
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2X+3<5
-3<-3
2X<2 divide by 2 on both side
2 2
X=1
gangescom
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|dw:1347312457904:dw|
gangescom
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your interval notation sould look something like this
its a bad drawing, and than draw the arrows (left or right)
Tombrokaw
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The solution would then look x<1
for the other one
phi
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if you started with
-7 ≤ 2x+3 < 5
you should get, after simplifying,
-5 ≤ x < 1
in interval notation, this is
[-5,1)
the square brackets indicates -5 is part of the interval.
) means the upper value is a limit, approached but not reached.
Tombrokaw
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Alright, thank you