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lilMissMindset
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two electric devices A & B are connected in parallel and the rms current in A is 15 A. If the current in B lags behind A by pi/2 radians and the line current is 23.4 A. Determine the current in B
 2 years ago
 2 years ago
lilMissMindset Group Title
two electric devices A & B are connected in parallel and the rms current in A is 15 A. If the current in B lags behind A by pi/2 radians and the line current is 23.4 A. Determine the current in B
 2 years ago
 2 years ago

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lilMissMindset Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 help me here please.
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
dw:1347318735842:dw Load B Lags A by 90 degrees. The line is the resultant you Pythagorean theorem
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{23.4^{2}15^{2}}\]
 2 years ago

lilMissMindset Group TitleBest ResponseYou've already chosen the best response.0
why subtract?
 2 years ago

lilMissMindset Group TitleBest ResponseYou've already chosen the best response.0
i get it why. lol
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
The line current is the resultant or the "total" In order to separate the total to the individual components, subtraction is the logical choice.
 2 years ago

lilMissMindset Group TitleBest ResponseYou've already chosen the best response.0
so that is the current in B?
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
Yes about 18 amps
 2 years ago

lilMissMindset Group TitleBest ResponseYou've already chosen the best response.0
another question, what is the difference between rms current and line current?
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
It is an inductive load when compared to the 15 amp load, or you could say the A is a capacitive load when compared to B. It is all relavent.
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
The line current is the combined currents of the two loads and is the current traveling to and fro from the power source. It is of course AC as we are talking RMS, all the currents in this problem is assumed to be measured in RMS units......including the line current.
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
Root Mean Square (RMS) is the most common value to measure AC, it is the value that DC current would produce as heat when the AC RMS value is converted to heat.
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
Kind of confusihng, but AC has several values of current/voltage. Peak Peak to Peak RMS (root mean square) Average
 2 years ago

lilMissMindset Group TitleBest ResponseYou've already chosen the best response.0
ok. thanks a lot! :)
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
Good luck, are you pursueing an electrical engineering major?
 2 years ago

lilMissMindset Group TitleBest ResponseYou've already chosen the best response.0
no. actually, my major is mechanical engineering, it's just that it's an elective course.
 2 years ago

lilMissMindset Group TitleBest ResponseYou've already chosen the best response.0
are you ana electrical engineer?
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
Understand, good luck with it, and I think you are getting into a great field.
 2 years ago

lilMissMindset Group TitleBest ResponseYou've already chosen the best response.0
thank you. :) hope i can make it. :)
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
Not a degreed EE, but an EE as far as the U.S. Government, I was a GS855 for the FAA for years. There are other methods to become an engineer, but I recommend the method you are going, a formal education with a degree.
 2 years ago

lilMissMindset Group TitleBest ResponseYou've already chosen the best response.0
i see. hail to all engineers. :)
 2 years ago
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