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Tombrokaw
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This one is a doozy.. X/x^24 (greater than or equal to sign) 0. How would I solve ?
 2 years ago
 2 years ago
Tombrokaw Group Title
This one is a doozy.. X/x^24 (greater than or equal to sign) 0. How would I solve ?
 2 years ago
 2 years ago

This Question is Closed

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
\[\frac x{x^2  4} \ge 0\] ???
 2 years ago

Tombrokaw Group TitleBest ResponseYou've already chosen the best response.0
yes that is the problem
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
cross multiply..what do you get?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
where did you get =?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
should be \(\ge\) not =
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
your initial sign was \(\ge\) so you can't change it
 2 years ago

Tombrokaw Group TitleBest ResponseYou've already chosen the best response.0
so my answer is correct ? or is there more to do ?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
nothing more
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
or if you want to be meticulous like other "mathematicians" note that x cannot be 2 or 2
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.0
Uh... @lgbasallote , that answer isn't right.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
you sure?
 2 years ago

Tombrokaw Group TitleBest ResponseYou've already chosen the best response.0
Oh ok, just making sure because I am supposed to solve this as an inequality and show a sign chart as well expressing in interval notation
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
then why don't you show how it's done, oh great one?
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.0
It's \(x\in (2, 0]\cup (2,\infty)\) Well, that's what I'm getting... let me check.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i did say x cannot be 2 or 2
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.0
According to Mathematica, that seems to be the case. And, I'm not trying to make you look bad or anything, jeez, it's a mistake, and it happens, don't take it personally. Check the boundaries yourself.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
you did read what i was saying right?
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.0
Yes, but, it's supposed to be: \[ x>2\\ 2<x\le 0 \]
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
I'd look at where x^34x is positive and negative...
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
simplest way I think...
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i didn't say any signs did i? i said x cannot be 2 or 2
 2 years ago

Tombrokaw Group TitleBest ResponseYou've already chosen the best response.0
So how does one get to this conclusion? If you dont mind me asking.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
and i was also insulting the mathematicians
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
multiply both sides by (x^24 )^2
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
I'm actually not sure what the 'standard' way is to look at these sorts of inequalities... I've forgotten maybe. Someone else might have a more kosher method.
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac x{x^2  4} \ge 0\] \[\frac x{(x2)(x+2)} \ge 0\] changes sign at \(2,0,2\) so only need to check on interval. say \(x<2\) i pick \(x=3\) we get \[\frac{3}{(3)^24}=\frac{3}{5}\] which is negative so it is negative, positive, negative, positive on the respective intervals \[(\infty,2), (2,0), (0,2), (2,\infty)\]
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.0
Here's a counter example to your solution: \[ x=1\ge0\\ \frac{1}{14}=\frac{1}{3}\not \ge\; 0 \]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
counter example to what?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
you're a mathematician @LolWolf ...you know that greater than and less than are under "inequalities" => not equal to and again i repeat...i was insulting the meticulousness of mathemeticians
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.0
(@lgbasallote 's not yours, @satellite73 , haha)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
anyway..if you don't need the domain of this then plain \(x \ge 0\) is fine
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
if it's a computer you're trying to please
 2 years ago

Tombrokaw Group TitleBest ResponseYou've already chosen the best response.0
Thank you. The other question I have goes like this : a^5/3 * b^2/3 * c^3 / C^2 * a^2/3 * b^4/3 .
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
add/subtract the exponents on like bases eg. : a^(2/3) * a^(5/3) = a^(7/3)
 2 years ago

Tombrokaw Group TitleBest ResponseYou've already chosen the best response.0
for example on (a) would leave denominator 3 alone and just add the numnerators?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
Hope you're not asking about adding fractions :P
 2 years ago

Tombrokaw Group TitleBest ResponseYou've already chosen the best response.0
My answer is A^1 * b^6/3 * c^5
 2 years ago

Tombrokaw Group TitleBest ResponseYou've already chosen the best response.0
would this be correct?
 2 years ago
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