Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

abannavong

I need AP Calculus help!!

  • one year ago
  • one year ago

  • This Question is Closed
  1. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    i will post the assignment soon!

    • one year ago
  2. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    Help with all plz!

    • one year ago
    1 Attachment
  3. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    • one year ago
    1 Attachment
  4. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    hi

    • one year ago
  5. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    the circled questions btw

    • one year ago
  6. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    for the first one, its just 8 thats posted?

    • one year ago
  7. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    i mean circled

    • one year ago
  8. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    its numbers 10, 14, 16, 18, 22

    • one year ago
  9. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    oh i was looking at the first one

    • one year ago
  10. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    kk

    • one year ago
  11. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    oh man, that second one's really hard to read lol so lets do the first one

    • one year ago
  12. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    kk

    • one year ago
  13. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    k so for 8 what is x approaching? i cant see

    • one year ago
  14. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    we dont have to do number 8 lol

    • one year ago
  15. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    :\ it looked circled to me lol

    • one year ago
  16. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    its only numbers 10, 14, 16, 18, 22

    • one year ago
  17. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    do you not have to do the problem in your first attachment?

    • one year ago
  18. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh yeah duh i forgot i do lolz

    • one year ago
  19. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    haha ok cool well i basically cant read any of them cuz they're blurry so can you just type out one that you need help with?

    • one year ago
  20. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    kk

    • one year ago
  21. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    hang on

    • one year ago
  22. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    number 8 its as x goes to infinity

    • one year ago
  23. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    so it's as x-> infinity of (2x^2)/(x^2 +3) ? is that right?

    • one year ago
  24. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    2x^5/ x^5+3

    • one year ago
  25. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    oh ok.

    • one year ago
  26. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    have y'all talked about L'Hospital's Rule yet?

    • one year ago
  27. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    i dont think so

    • one year ago
  28. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    k.

    • one year ago
  29. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    what is the L'hospitals rule? can u plz explain

    • one year ago
  30. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    i don't think you're supposed to use it if you haven't covered it yet. you don't need it anyway.

    • one year ago
  31. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    so you start by considering the terms with the highest exponents

    • one year ago
  32. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    if I remember correctly, since x is approaching infinity and it's a rational function, you can rewrite it only including the x's with the greatest exponents

    • one year ago
  33. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    so what would you have if you did that?

    • one year ago
  34. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    hang on im kinda confused

    • one year ago
  35. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    that's ok. so what i'm saying is your next step is to rewrite the limit excluding the +3 in the denominator

    • one year ago
  36. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    to exclude the +3 in the denominator how do u do tht?

    • one year ago
  37. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    you can do this because when x goes to infinity, 2x^5 and x^5 approach infinity and the 3 basically doesn't change the fraction anymore

    • one year ago
  38. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    because if you imagine really high numbers, say x=100, x^5 would be 10000000000 and 2x^5 would be 20000000000 and the +3 in the denominator makes less and less of a difference in the fraction. (10000000000/20000000003 is really close to 10000000000/20000000000)

    • one year ago
  39. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok

    • one year ago
  40. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    in other words, the fraction approaches 1/2

    • one year ago
  41. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    im sorry, it approaches 2

    • one year ago
  42. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    because 2x^5 is in the numerator

    • one year ago
  43. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok so ur limit is basically 2 then right?

    • one year ago
  44. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    yup

    • one year ago
  45. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok now i get number 8

    • one year ago
  46. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    so in questions like that, where x is approaching infinity, you can disregard any terms that arent the variables with the highest exponent. like if you had an x^4 being added/subtracted somewhere in the fraction, you could disregard that, too.

    • one year ago
  47. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    why can u?

    • one year ago
  48. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    for the same reason, because as x approaches infinity, they change the fraction less and less, even though it has x in it....those terms approach infinity slower than terms of higher powers.

    • one year ago
  49. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    im kinda confused on tht part

    • one year ago
  50. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    it's kind of counter-intuitive at first

    • one year ago
  51. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok

    • one year ago
  52. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    as x gets greater, the difference between x^5 and x^4 also gets greater. if x is 10, then x^5 is 100000 and x^4 is 10000, x^5 is 10 times greater than x^4. but when x= 100, x^5 becomes 100 times bigger than x^4, and so on, until x^5 is infinitely bigger than x^4 and you can disregard x^4.

    • one year ago
  53. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok now i get it

    • one year ago
  54. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    :) cool

    • one year ago
  55. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    can u help me with the continuity limits and one-sided ones those ones are the ones that r confusing

    • one year ago
  56. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    i can help w one more then i need to get my own work done haha

    • one year ago
  57. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    kk

    • one year ago
  58. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    so i guess pick one for us to do

    • one year ago
  59. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    kk

    • one year ago
  60. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    i think i get the rest on my THQ but i need help with the continuity ones

    • one year ago
  61. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    k

    • one year ago
  62. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    let me post the problem

    • one year ago
  63. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    kk

    • one year ago
  64. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\lim_{x \rightarrow 4-} \frac{ \sqrt{x}-2 }{ x-4 } \]

    • one year ago
  65. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    so first notice that when x = 4, f(x) = 0/0, which is undefined.

    • one year ago
  66. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah

    • one year ago
  67. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    and since x is approaching 4 from the left (less than 4, getting greater) both the numerator and denominator are going to be negative...do u get that?

    • one year ago
  68. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    can u explain it a bit more im still a bit confused

    • one year ago
  69. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    sure. so the way i think of it, is to basically imagine x as some number a little less than 4.. 3.something. when you plug that number into the denominator, 3.something - 4 is always going to be negative. (anything less than 4) - 4 will be negative, right? (3-4=-1, 3.5-4=-0.5, 3.99-4 = -0.01)

    • one year ago
  70. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh yeah so its like it keeps on approaching 4 right?

    • one year ago
  71. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    and for the numerator, you can imagine that since the square root of 4 is 2, the square root of anything less than 4 will be less than 2... when you subtract 2 from that number, the result is negative

    • one year ago
  72. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    ya it keeps approaching 4

    • one year ago
  73. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    but from the less-than-4 side because it has the minus sign (x->4-)

    • one year ago
  74. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    basically the limit for it will negative right?

    • one year ago
  75. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    well the numerator and denominator are both negative, right?

    • one year ago
  76. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    so the fraction comes out positive

    • one year ago
  77. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok

    • one year ago
  78. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    why r limits soo confusing :3

    • one year ago
  79. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    lol i know. wanna see my limit problem that no one will answer?

    • one year ago
  80. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    Limit as x->(pi/2) of [tanx+1/(x-pi/2)]?

    • one year ago
  81. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    thats my question that no one will answer :(

    • one year ago
  82. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    i had it on a quiz today

    • one year ago
  83. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    can u do the substitution method for tht one

    • one year ago
  84. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    i think

    • one year ago
  85. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    idk

    • one year ago
  86. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    no because tan of pi/2 is undefined, it goes to neg infinity and infinity from the right and left....

    • one year ago
  87. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh yeah ur right oops lol

    • one year ago
  88. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    ya...it's brutal.

    • one year ago
  89. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    anyway

    • one year ago
  90. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    but im still kinda confused on the continuity limits and one-sided ones

    • one year ago
  91. nj1202
    Best Response
    You've already chosen the best response.
    Medals 0

    oh boy satellite's here.... it's about to get real xD

    • one year ago
  92. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    i just realized that your problem is tricky. you need to factor your x-4 into (sqrt(x)-2)(sqrt(x)+2) then cancel out the numerator

    • one year ago
  93. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\lim_{ x\to\frac{\pi}{2}}\frac{\tan(x)+1}{x-\frac{\pi}{2}}\]?

    • one year ago
  94. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    oooh well that's my problem but not hers

    • one year ago
  95. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    mines posted

    • one year ago
  96. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    oh ok

    • one year ago
  97. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    somewhere down the list!

    • one year ago
  98. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    @jldstuff393 how do u do my problem kinda confuzzled

    • one year ago
  99. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    i know i know. u remember difference of squares? like (x^2 - 4) = (x-2)(x+2)?

    • one year ago
  100. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    is this the problem \[\lim_{x \rightarrow 4-} \frac{ \sqrt{x}-2 }{ x-4 }\]?

    • one year ago
  101. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh yeah i remember different of squares

    • one year ago
  102. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah @satellite73 thts my problem

    • one year ago
  103. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    so unless satellite has a less tricky way to solve it, you can factor (x-4) as a difference of squares... (sqrt(x)-2)(sqrt(x)+2)

    • one year ago
  104. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    does that make sense?

    • one year ago
  105. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    the gimmick here is to "rationalize the numerator" by multiplying by the conjugate of \(\sqrt{x}-2\) which is \(\sqrt{x}+2\)

    • one year ago
  106. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    cuz when u have that, you can cancel out the (sqrt(x)-2) in the numerator and denominator

    • one year ago
  107. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    so u multpily the top and bottom by \[\sqrt{x} +2 \]

    • one year ago
  108. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    this works because \((a+b)(a-b)=a^2-b^2\) and so \((\sqrt{x}-2)(\sqrt{x}+2)=x-4\)

    • one year ago
  109. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    that cancels with the \(x-4\) in the denominator, which is what you want, you want to cancel the zero

    • one year ago
  110. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    and x-4 can cancel in denominator

    • one year ago
  111. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok!

    • one year ago
  112. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    so ur limit is one right?

    • one year ago
  113. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    leaves you with \[\lim_{x \rightarrow 4} \frac{ \sqrt{x}-2 }{ x-4 }=\lim_{x \rightarrow 4} \frac{1 }{ \sqrt{x}+2}\]\]

    • one year ago
  114. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok i get

    • one year ago
  115. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    no limit is not one, now you have to replace \(x\) by 4

    • one year ago
  116. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    once u replace x with 4 u get 1/ 4 right?

    • one year ago
  117. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    yup

    • one year ago
  118. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    whenever you get \(\frac{0}{0}\) you need some gimmick to factor and cancel to get rid of the zeros

    • one year ago
  119. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    satellite would you mind helping me after you're done here? O.o good luck guys!

    • one year ago
  120. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok

    • one year ago
  121. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    sometime sit is easy sometimes it is a pain. but you get used to it

    • one year ago
  122. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    @satellite73 i have some more questions!

    • one year ago
  123. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    @jldstuff393 sure if i can what is the question

    • one year ago
  124. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    @abannavong go ahead and post them, i will look

    • one year ago
  125. jldstuff393
    Best Response
    You've already chosen the best response.
    Medals 2

    i'll repost it, thanks!

    • one year ago
  126. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    kk! thanks @satellite73

    • one year ago
  127. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    14, 16, and 18

    • one year ago
  128. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    i can't really read it, but for 16 replace \(x\) by 2 in both formulas if you get the same number, that is the limit if you get different numbers, there is no limit

    • one year ago
  129. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    number 14 its as deltax goes to 0 with the little plus sign

    • one year ago
  130. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    i can't read 18 either is it \(\lim_{ x\to 1^+}\) or \(\lim_{x\to 1^-}\)?

    • one year ago
  131. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    x-> 1+

    • one year ago
  132. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    then replace \(x\) by 1 in the second formula you get \(1-1=0\)

    • one year ago
  133. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok

    • one year ago
  134. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    can u help with 14 also

    • one year ago
  135. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    its confusing

    • one year ago
  136. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    sure, but i can't really read it can you post in a new question? you do not need to write \(\Delta x\) you can just write \(h\) instead

    • one year ago
  137. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    it is actually very straight forward we will do a little algebra and that is all

    • one year ago
  138. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    kk hang on dinner quickly

    • one year ago
  139. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    \[(x+h)^2+x+h-(x^2+x)=x^2+2xh+h^2+x+h-x^2-x\] \[\cancel{x^2}+2xh+h^2+\cancel{x}+h-\cancel{x^2}-\cancel{x}=2xh+h+h^2\] divide by \(h\) and get \(2x+1+h\) let \(h\to 0\) be replacing \(h\) by 0 and you get \(2x+1\)

    • one year ago
  140. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok! @satellite73 im back from dinner

    • one year ago
  141. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    that was a quick meal, you should take your time i wrote the solution above, but i used \(h\) instead of \(\Delta x\) it is mostly just algebra, to get rid of the factor of \(\Delta x\) in the denominator, then you replace it by 0

    • one year ago
  142. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    i did eat dinner

    • one year ago
  143. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    im eating and doing work lolz

    • one year ago
  144. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    you are either eating late or are on the left coast

    • one year ago
  145. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    im on the west coast lolz

    • one year ago
  146. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    after you finish eating, read my solution above i hope all the steps are clear they are almost all algebra steps, only at the end do you replace \(h\) by 0

    • one year ago
  147. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    kk

    • one year ago
  148. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok its jst basic algebra right? so u foil the (x+h)^2 right?

    • one year ago
  149. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    yes exactly it is \((x+h)(x+h)=x^2+2xh+h^2\)

    • one year ago
  150. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok and then from there u can combine the like terms and get 2xh+h+h^2

    • one year ago
  151. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    yes,

    • one year ago
  152. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    that is all in the numerator you get \[\frac{2xh+h+h^2}{h}\]

    • one year ago
  153. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    and then can u factor out the h on the numerator

    • one year ago
  154. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    yes factor and cancel or divide each term by \(h\) it is the same thing

    • one year ago
  155. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok and then u get 2x+1

    • one year ago
  156. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    yes

    • one year ago
  157. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok! i get tht now

    • one year ago
  158. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    whew that was exhausting

    • one year ago
  159. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\lim_{x \rightarrow2 ^{+}}(2x-\left[ \left| x \right| \right]\] help im confused with this one also

    • one year ago
  160. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    is that an absolute value sign?

    • one year ago
  161. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    or is that the floor function?

    • one year ago
  162. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    its like a bracket and then two straight lines inside

    • one year ago
  163. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    do you know what that function is called?

    • one year ago
  164. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    ughhh i dont remember what it was called

    • one year ago
  165. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    it is either called "floor" or "greatest integer"

    • one year ago
  166. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    is it kinda like a piecewise function or something like tht

    • one year ago
  167. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh yeah i remember!

    • one year ago
  168. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    so if \(x>2\) but close to 2, then \([x]=2\)

    • one year ago
  169. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    so you have \[\lim_{x\to 2}2x-2=4-2=2\]

    • one year ago
  170. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    to be more precise \[\lim_{x\to 2^+}2x-2=4-2=2\]

    • one year ago
  171. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok! at first it seemed confusing but oh ok now i get it!

    • one year ago
  172. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    whereas \[\lim_{x\to 2^-}2x-2=4-1=3\] because if \(x<2\) but close to 2, then \([x]=1\)

    • one year ago
  173. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok! tht seems soo much easier now!

    • one year ago
  174. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    yes if you know what it means it is not hard here is a nice picture of \(y=2x-[x]\) http://www.wolframalpha.com/input/?i=2x-floor%28x%29

    • one year ago
  175. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok! i get it! i have another question again hang on

    • one year ago
  176. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    so it says find the x-values(if any) at which f is not continuous. which of the discontinuities are removable. f(x)= 1/ x^2+1

    • one year ago
  177. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    \[f(x)=\frac{1}{x^2+1}\] has no discontinuities, since it is a rational function and the denominator is never 0 since \(x^2\geq 0\) for any \(x\) you can see that \(x^2+1\geq 1\) no matter what \(x\) is, so this function has no discontinuities. as the denominator is never zero

    • one year ago
  178. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok thank you @satellite73

    • one year ago
  179. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    you are welcome enough math, study something else or do something more constructive

    • one year ago
  180. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    pretty much tht was my last problem! time to find a prayer for theology class! thank you @satellite73 and study for english test tomorrow on grapes of wrath

    • one year ago
  181. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    good luck with the joads

    • one year ago
  182. abannavong
    Best Response
    You've already chosen the best response.
    Medals 0

    lolz thanks i have to find the intercalary chapters to write about :3 i dont even know what those r

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.