Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

i will post the assignment soon!

Help with all plz!

hi

the circled questions btw

for the first one, its just 8 thats posted?

i mean circled

its numbers 10, 14, 16, 18, 22

oh i was looking at the first one

kk

oh man, that second one's really hard to read lol so lets do the first one

kk

k so for 8 what is x approaching? i cant see

we dont have to do number 8 lol

:\ it looked circled to me lol

its only numbers 10, 14, 16, 18, 22

do you not have to do the problem in your first attachment?

oh yeah duh i forgot i do lolz

kk

hang on

number 8 its as x goes to infinity

so it's as x-> infinity of (2x^2)/(x^2 +3) ? is that right?

2x^5/ x^5+3

oh ok.

have y'all talked about L'Hospital's Rule yet?

i dont think so

k.

what is the L'hospitals rule? can u plz explain

i don't think you're supposed to use it if you haven't covered it yet. you don't need it anyway.

so you start by considering the terms with the highest exponents

so what would you have if you did that?

hang on im kinda confused

to exclude the +3 in the denominator how do u do tht?

oh ok

in other words, the fraction approaches 1/2

im sorry, it approaches 2

because 2x^5 is in the numerator

oh ok so ur limit is basically 2 then right?

yup

oh ok now i get number 8

why can u?

im kinda confused on tht part

it's kind of counter-intuitive at first

oh ok

oh ok now i get it

:) cool

can u help me with the continuity limits and one-sided ones those ones are the ones that r confusing

i can help w one more then i need to get my own work done haha

kk

so i guess pick one for us to do

kk

i think i get the rest on my THQ but i need help with the continuity ones

let me post the problem

kk

\[\lim_{x \rightarrow 4-} \frac{ \sqrt{x}-2 }{ x-4 } \]

so first notice that when x = 4, f(x) = 0/0, which is undefined.

yeah

can u explain it a bit more im still a bit confused

oh yeah so its like it keeps on approaching 4 right?

ya it keeps approaching 4

but from the less-than-4 side because it has the minus sign (x->4-)

basically the limit for it will negative right?

well the numerator and denominator are both negative, right?

so the fraction comes out positive

oh ok

why r limits soo confusing :3

lol i know. wanna see my limit problem that no one will answer?

Limit as x->(pi/2) of [tanx+1/(x-pi/2)]?

thats my question that no one will answer :(

i had it on a quiz today

can u do the substitution method for tht one

i think

idk

oh yeah ur right oops lol

ya...it's brutal.

anyway

but im still kinda confused on the continuity limits and one-sided ones

oh boy satellite's here.... it's about to get real xD

\[\lim_{ x\to\frac{\pi}{2}}\frac{\tan(x)+1}{x-\frac{\pi}{2}}\]?

oooh well that's my problem but not hers

mines posted

oh ok

somewhere down the list!

@jldstuff393 how do u do my problem kinda confuzzled

i know i know. u remember difference of squares? like (x^2 - 4) = (x-2)(x+2)?

is this the problem
\[\lim_{x \rightarrow 4-} \frac{ \sqrt{x}-2 }{ x-4 }\]?

oh yeah i remember different of squares

yeah @satellite73 thts my problem

does that make sense?

cuz when u have that, you can cancel out the (sqrt(x)-2) in the numerator and denominator

so u multpily the top and bottom by \[\sqrt{x} +2 \]

this works because \((a+b)(a-b)=a^2-b^2\) and so \((\sqrt{x}-2)(\sqrt{x}+2)=x-4\)

and x-4 can cancel in denominator

oh ok!

so ur limit is one right?

oh ok i get

no limit is not one, now you have to replace \(x\) by 4

once u replace x with 4 u get 1/ 4 right?

yup

whenever you get \(\frac{0}{0}\) you need some gimmick to factor and cancel to get rid of the zeros

satellite would you mind helping me after you're done here? O.o good luck guys!

oh ok

sometime sit is easy
sometimes it is a pain.
but you get used to it

@satellite73 i have some more questions!

@jldstuff393 sure if i can
what is the question

@abannavong go ahead and post them, i will look

i'll repost it, thanks!

kk! thanks @satellite73

14, 16, and 18

number 14 its as deltax goes to 0 with the little plus sign

i can't read 18 either
is it \(\lim_{ x\to 1^+}\) or \(\lim_{x\to 1^-}\)?

x-> 1+

then replace \(x\) by 1 in the second formula
you get \(1-1=0\)

oh ok

can u help with 14 also

its confusing

it is actually very straight forward
we will do a little algebra and that is all

kk hang on dinner quickly

oh ok! @satellite73 im back from dinner

i did eat dinner

im eating and doing work lolz

you are either eating late or are on the left coast

im on the west coast lolz

kk

oh ok its jst basic algebra right? so u foil the (x+h)^2 right?

yes exactly
it is \((x+h)(x+h)=x^2+2xh+h^2\)

oh ok and then from there u can combine the like terms and get 2xh+h+h^2

yes,

that is all in the numerator
you get
\[\frac{2xh+h+h^2}{h}\]

and then can u factor out the h on the numerator

yes factor and cancel or divide each term by \(h\) it is the same thing

oh ok and then u get 2x+1

yes

oh ok! i get tht now

whew that was exhausting

is that an absolute value sign?

or is that the floor function?

its like a bracket and then two straight lines inside

do you know what that function is called?

ughhh i dont remember what it was called

it is either called "floor" or "greatest integer"

is it kinda like a piecewise function or something like tht

oh yeah i remember!

so if \(x>2\) but close to 2, then \([x]=2\)

so you have
\[\lim_{x\to 2}2x-2=4-2=2\]

to be more precise
\[\lim_{x\to 2^+}2x-2=4-2=2\]

oh ok! at first it seemed confusing but oh ok now i get it!

whereas
\[\lim_{x\to 2^-}2x-2=4-1=3\] because if \(x<2\) but close to 2, then \([x]=1\)

oh ok! tht seems soo much easier now!

oh ok! i get it! i have another question again hang on

oh ok thank you @satellite73

you are welcome
enough math, study something else
or do something more constructive

good luck with the joads

lolz thanks i have to find the intercalary chapters to write about :3 i dont even know what those r