## Tombrokaw Group Title Cube root p^7*r5 2 years ago 2 years ago

1. nickhouraney

$\sqrt[3]{p^7r^5}$ correct?

2. Tombrokaw

Si senor!

3. nickhouraney

so if you just pull out the variables in 3s and leave whats left behind you would end up with...

4. Tombrokaw

P4 R2 in the root

5. nickhouraney

you call pull out one more P

6. Tombrokaw

how?

7. Tombrokaw

At this point we have P3 R3 and inside the root p4 r 2

8. nickhouraney

ya but if were pulling out the variables in 3's then we can take out 2P's from that P^7

9. nickhouraney

well be left with P in the cube root from that variable

10. Tombrokaw

So it would be P^2 and R1 on the outside of the cube root?

11. nickhouraney

correct

12. nickhouraney

with PR^2 on the inside

13. Tombrokaw

and on the inside P and r2 and it would be simplified

14. nickhouraney

yup

15. Tombrokaw

Perfect! Thank you