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\[\sqrt[3]{p^7r^5}\] correct?

Si senor!

so if you just pull out the variables in 3s and leave whats left behind you would end up with...

P4 R2
in the root

you call pull out one more P

how?

At this point we have P3 R3 and inside the root p4 r 2

ya but if were pulling out the variables in 3's then we can take out 2P's from that P^7

well be left with P in the cube root from that variable

So it would be P^2 and R1 on the outside of the cube root?

correct

with PR^2 on the inside

and on the inside P and r2
and it would be simplified

yup

Perfect! Thank you