Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
ilikephysics2
Group Title
for a spherical object what is its mass in terms of the density of the material, its diameter and any necessary constants?
 one year ago
 one year ago
ilikephysics2 Group Title
for a spherical object what is its mass in terms of the density of the material, its diameter and any necessary constants?
 one year ago
 one year ago

This Question is Closed

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
well volume of a sphere is \[\frac 43 \pi r^3\]
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
and then density = mass/volume
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
\[\rho=\frac mV\] \[m=V\rho\]
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
so you have \[m = \frac 43\rho \pi r^3\]
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
where \(\rho\) = density
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
what about its diameter
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
change r to d/2
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
and \(r\) is the radius (half the diameter) \(r=\frac d2\)
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
radius = diameter/2 so just change r to d/2
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
ok so thats the final solution?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
replace r with d/2....
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
ok cool and can i give you guys both metals or does just one of you get it?
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
hey so its (4/3)p(pi)(d/2)^3
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
is that right?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
you can simplify the numbers a bit
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
unkle...it won't let me give you a metal now
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
why cant i give it to both of you
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
i dont mind about that
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
\[m=\frac43\rho\pi\left(\frac d2\right)^3\] use \[\left(\frac{a}{b}\right)^n=\frac {a^n} {b^n}\]
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
so it simplifies to 4p(pi)(d/2)?
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
i crossed out the 3's
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
what he meant was distribute the exponent
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
you can not cancel an index with denominator like that
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
oh so whats it turn to?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
\[\left(\frac{a}{b}\right)^n=\frac {a^n} {b^n}\] \[\left(\frac{d}{2}\right)^3=\frac {d^3} {2^3}\]
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
thanks :)
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
can you simplify the numbers in the equation now?
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
yes (4/3)p(pi)(d^3/8) ?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
you can simplify it further
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
you can multiply the denominators
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
so 4p(pi)(d/8) ? ?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
what happened?
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
can you simplify it?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
you canceled the denominaotr and teh exponent???
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
it can't be simplified?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
it can...you just simplified it wrong....multiply the denominators
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
don't touch anything else
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
so it (4/24)p(pi)(d^3) ?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
thats better!
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
yes. now express 4/24 in lowest terms
 one year ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
ok so 1/6 p(pi)(d^3) ? thats final!!!!
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
right!!
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
your turn @UnkleRhaukus
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
\[\color{red}\checkmark\]
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
so the constants necessary to express the volume in terms of diameter are ; the natural number; 6 the density of the material rho; \(\rho\) the geometrical constant pi; \(\pi\) the diameter of the sphere \(d\) and the dimensional constant \(3\)
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.