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Akshit_math
 2 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{1 + 2008\sqrt{1 + 2009\sqrt{1 + 2010\sqrt{1 + 2011.2013}}}}\]

Akshit_math
 2 years ago
Best ResponseYou've already chosen the best response.0what is the value of the above ???

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.0do you have access to a calculator? or do you want to solve it by hand?

Akshit_math
 2 years ago
Best ResponseYou've already chosen the best response.0we are Indians and here most of the time its by hand ...so please try to solve and help me out without the use of calculator,,

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.3ok, now can u write 2011*2013 as (20121)(2012+1) ?? and do u know what (a+b)(ab) =??

Akshit_math
 2 years ago
Best ResponseYou've already chosen the best response.0yeah \[(a+b)(ab)=a ^{2}b ^{2}\]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.3good, so what will be (20121)(2012+1) =??

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.3and u had 1+ 2011*2013 so now whats 1+2012^21 ??

Akshit_math
 2 years ago
Best ResponseYou've already chosen the best response.0heyyyyy thaaaanzzznnzzzz buddy i got it all after dat ...u made it so easy 4 me now!!!...champ!!!..thnak u!

Akshit_math
 2 years ago
Best ResponseYou've already chosen the best response.0hey @sriramkumar u typing since long tym eh!

sriramkumar
 2 years ago
Best ResponseYou've already chosen the best response.1let 2012=a, then the problemn becomes \[\sqrt{1+(a4)\sqrt{1+(a3)\sqrt{1+(a2)\sqrt{1+(a1)(a+1)}}}}\] then the inner root becomes \[a ^{2}1 +1=a ^{2}\] \[1+(a2)\sqrt{a ^{2}}=1+(a2)a=1+a ^{2}2a=(a1)^{2}\] ...... and so on....

Akshit_math
 2 years ago
Best ResponseYou've already chosen the best response.0damn gud!!!....@sriramkumar

Akshit_math
 2 years ago
Best ResponseYou've already chosen the best response.0n the answer is 2009
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