Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

The value of _____

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
is _______
\[\sqrt{1 + 2008\sqrt{1 + 2009\sqrt{1 + 2010\sqrt{1 + 2011.2013}}}}\]
what is the value of the above ???

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

do you have access to a calculator? or do you want to solve it by hand?
we are Indians and here most of the time its by hand ...so please try to solve and help me out without the use of calculator,,
ok, now can u write 2011*2013 as (2012-1)(2012+1) ?? and do u know what (a+b)(a-b) =??
yeah \[(a+b)(a-b)=a ^{2}-b ^{2}\]
good, so what will be (2012-1)(2012+1) =??
\[2012^{2}-1\]
and u had 1+ 2011*2013 so now whats 1+2012^2-1 ??
heyyyyy thaaaanzzznnzzzz buddy i got it all after dat ...u made it so easy 4 me now!!!...champ!!!..thnak u!
welcome :)
hey @sriramkumar u typing since long tym eh!
let 2012=a, then the problemn becomes \[\sqrt{1+(a-4)\sqrt{1+(a-3)\sqrt{1+(a-2)\sqrt{1+(a-1)(a+1)}}}}\] then the inner root becomes \[a ^{2}-1 +1=a ^{2}\] \[1+(a-2)\sqrt{a ^{2}}=1+(a-2)a=1+a ^{2}-2a=(a-1)^{2}\] ...... and so on....
damn gud!!!....@sriramkumar
n the answer is 2009

Not the answer you are looking for?

Search for more explanations.

Ask your own question