anonymous
  • anonymous
What would the domain and range be?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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andriod09
  • andriod09
doamin is the x in a graph, while the range would be the y
anonymous
  • anonymous
What would it be in the following attached docs?

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More answers

andriod09
  • andriod09
|dw:1347377860332:dw|
andriod09
  • andriod09
use that. you have to answer the equations first.
anonymous
  • anonymous
This is what the problems looked like. And the ones I attached earlier are the answers.
andriod09
  • andriod09
the first numbers are x and the y are the last numbers
anonymous
  • anonymous
So what would it be?
anonymous
  • anonymous
I have graphed it and everything.
andriod09
  • andriod09
so you good?
anonymous
  • anonymous
No
hartnn
  • hartnn
u need domain and range of P(s)=69.70s-1077 right?
anonymous
  • anonymous
Yes
hartnn
  • hartnn
what values can s take ? any ?
anonymous
  • anonymous
What do you mean?
hartnn
  • hartnn
is there any restriction on value of s ?
anonymous
  • anonymous
First I found P(0) which equals (0, -1077). Then I found P(s) which equals (15.45, 0)
anonymous
  • anonymous
Those are the two points. Now I have to graph it and then find the domain and range.
pradipgr817
  • pradipgr817
in order to make profit domain should be [16, max no of radio available] correspondingly you can find range.
anonymous
  • anonymous
Wouldn't the domain be [0,-1077]?
pradipgr817
  • pradipgr817
lets say total no. of radio is a your function is P(s)=69.70s-1077 values of s is the domain at s=15.45 break even point occurs so at this point P(s)=0 But radio quantity is in integer so s=16. Nowo if he sells more than this only he will get profit i.e., [16 a] at 16 P(s)=0 and at s=a, P(a), so range is [P(16) P(a)]=[0 P(a)]
pradipgr817
  • pradipgr817
Is it clear?
anonymous
  • anonymous
I don't get it.
pradipgr817
  • pradipgr817
:(
anonymous
  • anonymous
So would range be [0, 15.45]?
pradipgr817
  • pradipgr817
lets solve together. you start I'll correct you
anonymous
  • anonymous
I have already solved it earlier. [0, -1077] and [15.45, 0]
anonymous
  • anonymous
Now the directions say to graph these points and then determine the domain and range.
pradipgr817
  • pradipgr817
in that answer is correct your domain is (0 infinity) [all possibilities included]
anonymous
  • anonymous
So what's the range?
pradipgr817
  • pradipgr817
[-1077 infinity)
anonymous
  • anonymous
Okay so Domain is [0, infinity) and Range is [-1077, infinity). Correct?
pradipgr817
  • pradipgr817
yes
anonymous
  • anonymous
Why wouldn't the domain be [0, 15.45]?
pradipgr817
  • pradipgr817
first of all no. of radio cannot be 15.45
anonymous
  • anonymous
Nevermind, I got it. Can you help me with one more problem?
pradipgr817
  • pradipgr817
second during this part only loss will occur. what about the profits? it will occur after your 15.45 so extend your range. finally max. no. of radio are not given so infinite number can exist. therefore domain is [0 infinity), not below zero as number of radio cannot be negative
pradipgr817
  • pradipgr817
Yea sure please ask. If I'll be able to help I'll surely do.
anonymous
  • anonymous
pradipgr817
  • pradipgr817
all parts?
anonymous
  • anonymous
Yes
pradipgr817
  • pradipgr817
a) (8, 45.7), (11, 48.1)
anonymous
  • anonymous
Okay
anonymous
  • anonymous
Is (b) y = .8x+39.3 ?
pradipgr817
  • pradipgr817
you put the values of x and y in equation and solve it. I haven't solved it. To check you got it right put the know value and check the answer
pradipgr817
  • pradipgr817
*known
anonymous
  • anonymous
m = 48.1-45.7/11-8 = -2.4/3 = .8 y-y1=m(x-x1) y-45.7 = .8(x-8) y-45.7 = .8x-6.4 y = .8x+39.3
pradipgr817
  • pradipgr817
yes. you got it.
pradipgr817
  • pradipgr817
put x=15 and obtain output
anonymous
  • anonymous
I got I = 51.3
pradipgr817
  • pradipgr817
so can you interpret the results?
anonymous
  • anonymous
"In 2015, PA's per capita income was $51.3 thousand." ??
pradipgr817
  • pradipgr817
will be
anonymous
  • anonymous
Okay
pradipgr817
  • pradipgr817
what about the trend?
anonymous
  • anonymous
I have no clue.
pradipgr817
  • pradipgr817
Initially in 2000, the income was 39.3 (your intercept). This per capita income increases unifomly, whose rate is given by the slope of the curve, which is 0.8.
pradipgr817
  • pradipgr817
and as the time will progress the per capita income will increase only. as per the equation, with increase in time it cannot decrease.
pradipgr817
  • pradipgr817
I hope you got it?
anonymous
  • anonymous
Yes, I got it.
pradipgr817
  • pradipgr817
:)
anonymous
  • anonymous
I need help with a few more whenever you're free.
pradipgr817
  • pradipgr817
ok no problem.
anonymous
  • anonymous
pradipgr817
  • pradipgr817
which part?
pradipgr817
  • pradipgr817
hey u thr? Is (a) solved.
anonymous
  • anonymous
No. Neither of them are solved. I don't understand any of the parts.
pradipgr817
  • pradipgr817
use this to solve (a) http://en.wikipedia.org/wiki/Simple_linear_regression
pradipgr817
  • pradipgr817
you need to fit the data given to a equation.
anonymous
  • anonymous
Okay
pradipgr817
  • pradipgr817
the line will be y=mx+c form.
pradipgr817
  • pradipgr817
find m first using the equations on web page(beta) then find c( alpha on web page)
pradipgr817
  • pradipgr817
let me know when you got something.
anonymous
  • anonymous
Honestly, I have no idea how to do this.
pradipgr817
  • pradipgr817
giv me 5 min
pradipgr817
  • pradipgr817
see, t is years sine 2000. So subtract 2000 from years. You have 5, 7...11 as x. and ticket cost is y
pradipgr817
  • pradipgr817
now find the average of x and y separately.
pradipgr817
  • pradipgr817
got upto this?
anonymous
  • anonymous
How would I find the average of x and y?
pradipgr817
  • pradipgr817
sum all numbers of x and divide by total number of values of x, similarly for y
pradipgr817
  • pradipgr817
use this it will help http://www2.isye.gatech.edu/~sman/courses/6739/SimpleLinearRegression.pdf
pradipgr817
  • pradipgr817
on page 9 formula are written use them.

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