At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
doamin is the x in a graph, while the range would be the y
What would it be in the following attached docs?
use that. you have to answer the equations first.
the first numbers are x and the y are the last numbers
So what would it be?
I have graphed it and everything.
so you good?
u need domain and range of P(s)=69.70s-1077 right?
what values can s take ? any ?
What do you mean?
is there any restriction on value of s ?
First I found P(0) which equals (0, -1077). Then I found P(s) which equals (15.45, 0)
Those are the two points. Now I have to graph it and then find the domain and range.
in order to make profit domain should be [16, max no of radio available] correspondingly you can find range.
Wouldn't the domain be [0,-1077]?
lets say total no. of radio is a your function is P(s)=69.70s-1077 values of s is the domain at s=15.45 break even point occurs so at this point P(s)=0 But radio quantity is in integer so s=16. Nowo if he sells more than this only he will get profit i.e., [16 a] at 16 P(s)=0 and at s=a, P(a), so range is [P(16) P(a)]=[0 P(a)]
Is it clear?
I don't get it.
So would range be [0, 15.45]?
lets solve together. you start I'll correct you
I have already solved it earlier. [0, -1077] and [15.45, 0]
Now the directions say to graph these points and then determine the domain and range.
in that answer is correct your domain is (0 infinity) [all possibilities included]
So what's the range?
Okay so Domain is [0, infinity) and Range is [-1077, infinity). Correct?
Why wouldn't the domain be [0, 15.45]?
first of all no. of radio cannot be 15.45
Nevermind, I got it. Can you help me with one more problem?
second during this part only loss will occur. what about the profits? it will occur after your 15.45 so extend your range. finally max. no. of radio are not given so infinite number can exist. therefore domain is [0 infinity), not below zero as number of radio cannot be negative
Yea sure please ask. If I'll be able to help I'll surely do.
a) (8, 45.7), (11, 48.1)
Is (b) y = .8x+39.3 ?
you put the values of x and y in equation and solve it. I haven't solved it. To check you got it right put the know value and check the answer
m = 48.1-45.7/11-8 = -2.4/3 = .8 y-y1=m(x-x1) y-45.7 = .8(x-8) y-45.7 = .8x-6.4 y = .8x+39.3
yes. you got it.
put x=15 and obtain output
I got I = 51.3
so can you interpret the results?
"In 2015, PA's per capita income was $51.3 thousand." ??
what about the trend?
I have no clue.
Initially in 2000, the income was 39.3 (your intercept). This per capita income increases unifomly, whose rate is given by the slope of the curve, which is 0.8.
and as the time will progress the per capita income will increase only. as per the equation, with increase in time it cannot decrease.
I hope you got it?
Yes, I got it.
I need help with a few more whenever you're free.
ok no problem.
hey u thr? Is (a) solved.
No. Neither of them are solved. I don't understand any of the parts.
use this to solve (a) http://en.wikipedia.org/wiki/Simple_linear_regression
you need to fit the data given to a equation.
the line will be y=mx+c form.
find m first using the equations on web page(beta) then find c( alpha on web page)
let me know when you got something.
Honestly, I have no idea how to do this.
giv me 5 min
see, t is years sine 2000. So subtract 2000 from years. You have 5, 7...11 as x. and ticket cost is y
now find the average of x and y separately.
got upto this?
How would I find the average of x and y?
sum all numbers of x and divide by total number of values of x, similarly for y
use this it will help http://www2.isye.gatech.edu/~sman/courses/6739/SimpleLinearRegression.pdf
on page 9 formula are written use them.