What would the domain and range be?

- anonymous

What would the domain and range be?

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- schrodinger

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- andriod09

doamin is the x in a graph, while the range would be the y

- anonymous

- anonymous

What would it be in the following attached docs?

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## More answers

- andriod09

|dw:1347377860332:dw|

- andriod09

use that. you have to answer the equations first.

- anonymous

This is what the problems looked like. And the ones I attached earlier are the answers.

##### 1 Attachment

- andriod09

the first numbers are x and the y are the last numbers

- anonymous

So what would it be?

- anonymous

I have graphed it and everything.

- andriod09

so you good?

- anonymous

No

- hartnn

u need domain and range of
P(s)=69.70s-1077
right?

- anonymous

Yes

- hartnn

what values can s take ? any ?

- anonymous

What do you mean?

- hartnn

is there any restriction on value of s ?

- anonymous

First I found P(0) which equals (0, -1077). Then I found P(s) which equals (15.45, 0)

- anonymous

Those are the two points. Now I have to graph it and then find the domain and range.

- pradipgr817

in order to make profit domain should be [16, max no of radio available]
correspondingly you can find range.

- anonymous

Wouldn't the domain be [0,-1077]?

- pradipgr817

lets say total no. of radio is a
your function is P(s)=69.70s-1077
values of s is the domain
at s=15.45 break even point occurs so at this point P(s)=0
But radio quantity is in integer so s=16. Nowo if he sells more than this only he will get profit i.e.,
[16 a]
at 16 P(s)=0 and at s=a, P(a), so range is [P(16) P(a)]=[0 P(a)]

- pradipgr817

Is it clear?

- anonymous

I don't get it.

- pradipgr817

:(

- anonymous

So would range be [0, 15.45]?

- pradipgr817

lets solve together. you start I'll correct you

- anonymous

I have already solved it earlier. [0, -1077] and [15.45, 0]

- anonymous

Now the directions say to graph these points and then determine the domain and range.

- pradipgr817

in that answer is correct your domain is (0 infinity) [all possibilities included]

- anonymous

So what's the range?

- pradipgr817

[-1077 infinity)

- anonymous

Okay so Domain is [0, infinity) and Range is [-1077, infinity). Correct?

- pradipgr817

yes

- anonymous

Why wouldn't the domain be [0, 15.45]?

- pradipgr817

first of all no. of radio cannot be 15.45

- anonymous

Nevermind, I got it. Can you help me with one more problem?

- pradipgr817

second during this part only loss will occur. what about the profits?
it will occur after your 15.45 so extend your range.
finally max. no. of radio are not given so infinite number can exist. therefore domain is
[0 infinity), not below zero as number of radio cannot be negative

- pradipgr817

Yea sure please ask. If I'll be able to help I'll surely do.

- anonymous

##### 1 Attachment

- pradipgr817

all parts?

- anonymous

Yes

- pradipgr817

a)
(8, 45.7), (11, 48.1)

- anonymous

Okay

- anonymous

Is (b) y = .8x+39.3 ?

- pradipgr817

you put the values of x and y in equation and solve it.
I haven't solved it. To check you got it right put the know value and check the answer

- pradipgr817

*known

- anonymous

m = 48.1-45.7/11-8 = -2.4/3 = .8
y-y1=m(x-x1)
y-45.7 = .8(x-8)
y-45.7 = .8x-6.4
y = .8x+39.3

- pradipgr817

yes. you got it.

- pradipgr817

put x=15 and obtain output

- anonymous

I got I = 51.3

- pradipgr817

so can you interpret the results?

- anonymous

"In 2015, PA's per capita income was $51.3 thousand." ??

- pradipgr817

will be

- anonymous

Okay

- pradipgr817

what about the trend?

- anonymous

I have no clue.

- pradipgr817

Initially in 2000, the income was 39.3 (your intercept). This per capita income increases unifomly, whose rate is given by the slope of the curve, which is 0.8.

- pradipgr817

and as the time will progress the per capita income will increase only. as per the equation, with increase in time it cannot decrease.

- pradipgr817

I hope you got it?

- anonymous

Yes, I got it.

- pradipgr817

:)

- anonymous

I need help with a few more whenever you're free.

- pradipgr817

ok no problem.

- anonymous

##### 1 Attachment

- pradipgr817

which part?

- pradipgr817

hey u thr? Is (a) solved.

- anonymous

No. Neither of them are solved. I don't understand any of the parts.

- pradipgr817

use this to solve (a) http://en.wikipedia.org/wiki/Simple_linear_regression

- pradipgr817

you need to fit the data given to a equation.

- anonymous

Okay

- pradipgr817

the line will be y=mx+c form.

- pradipgr817

find m first using the equations on web page(beta)
then find c( alpha on web page)

- pradipgr817

let me know when you got something.

- anonymous

Honestly, I have no idea how to do this.

- pradipgr817

giv me 5 min

- pradipgr817

see, t is years sine 2000. So subtract 2000 from years. You have 5, 7...11 as x. and ticket cost is y

- pradipgr817

now find the average of x and y separately.

- pradipgr817

got upto this?

- anonymous

How would I find the average of x and y?

- pradipgr817

sum all numbers of x and divide by total number of values of x, similarly for y

- pradipgr817

use this it will help http://www2.isye.gatech.edu/~sman/courses/6739/SimpleLinearRegression.pdf

- pradipgr817

on page 9 formula are written use them.

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