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KingGeorgeBest ResponseYou've already chosen the best response.2
First up, you need to find what \(\log_2(8)\) is. Can you tell me what that is?
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.2
Right. It's 3. So now you have the equation \[1+\lfloor3\rfloor\]Can you finish it from here? Or do you need some help with the floor function?
 one year ago

johnnydiamond08Best ResponseYou've already chosen the best response.0
So it would be 4 then?
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.2
Looks perfect to me.
 one year ago

johnnydiamond08Best ResponseYou've already chosen the best response.0
Okay so just to make sure I know what I'm doing. All you do is find what X would be and then add one to it?
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.2
The floor function is a bit weird. For example, if you had \[1+\left\lfloor \log_2(9)\right\rfloor\]instead, you would simplify as follows. Since \(\log_2(9)\approx 3.17\), you have\[1+\left\lfloor \log_2(9)\right\rfloor\\ 1+\left\lfloor 3.17\right\rfloor \\ 1+3 \\ 4\] In general, the floor function gets rid of any numbers to the right of the decimal place.
 one year ago

johnnydiamond08Best ResponseYou've already chosen the best response.0
Ah alright. We're doing all this stuff by hand so my professor is making it pretty easy for us. Thank you KingGeorge, you've been a lot of help!
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.2
Formally, \[\left\lfloor x\right\rfloor=\text{max}\{m\in\mathbb{Z} \;m<x\]In laymans terms, the greatest integer that is not greater than \(x\).
 one year ago

johnnydiamond08Best ResponseYou've already chosen the best response.0
So following the same equation but making X 123,456 the answer would be 17.
 one year ago
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