eli123
factor 21x^249x9x21



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eli123
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idk how i got 7x(3x7) 3(3x7) and i know its wrong

hartnn
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is the original problem
21x^258x21 ?

eli123
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no

eli123
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hartnn
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right,so thats 21x^240x21=0
right ?

eli123
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yeah and then the product of 21 and 21 is 441 and then 40 so the two numbers are 49 and 9

hartnn
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that is correct,
see above u have written 49x  9x
instead of what u got now as
49x+9x

eli123
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oooh i see wow

hartnn
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now whats common from first 2 terms in
21x^249x9x21 =0?

eli123
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7x

eli123
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i got the answer :P 3/7 and 7/3

hartnn
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yup, correct.

eli123
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im having problems with another equation

hartnn
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which ?

eli123
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eli123
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i got to the point 9 + or  sqrt of 1 all over 4

hartnn
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9 from where ?

hartnn
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Compare your quadratic equation with \(ax^2+bx+c=0\)
find a,b,c
then the two rots of x are:
\(\huge{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\)

eli123
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yeah b is 9

hartnn
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nopes, b is 4

eli123
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oh wait nooo i gave you the wrong equation! no wonder

hartnn
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lol :P

eli123
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hartnn
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still b is 9

eli123
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but in that equation it says b so (9) is 9

eli123
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inside i did put put 9^2 = 81

hartnn
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yes, u are correct
\(\huge\frac{9 \pm \sqrt{1}}{4}=\frac{10}{4},\frac{8}{4}\)

eli123
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wait you are just adding and subtracting the 1?

eli123
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obviously lol never mind i feel stupid

hartnn
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got it now ?

eli123
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yes, it was a stupid moment :P

eli123
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ok i did another one and i got 4+sqrt of 28 all over 2 @hartnn

hartnn
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question ?

eli123
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its the first one that sent you

eli123
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hartnn
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thats correct :)

eli123
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but how do i factor it?

hartnn
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do u want to factor or do u want to use quadratic formula?
anyways its not factorable....

eli123
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so what would be the answer?

eli123
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i cant simplify it?

hartnn
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all u can do is
\(2 \pm \sqrt7\)

hartnn
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\(\sqrt{28}=2\sqrt7\)

eli123
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how does that equal to that

hartnn
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\(\sqrt{28}=\sqrt{7*4}=\sqrt{7}\sqrt{4}=2\sqrt{7}\)

eli123
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got it

eli123
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you are the best!

hartnn
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lol. glad to hear that :)
u too are awesome ;)

eli123
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lol thank you, well i gotta keep doing this stupid hw

hartnn
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best of luck for that.