anonymous
  • anonymous
factor 21x^2-49x-9x-21
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
idk how i got 7x(3x-7) 3(3x-7) and i know its wrong
hartnn
  • hartnn
is the original problem 21x^2-58x-21 ?
anonymous
  • anonymous
no

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
hartnn
  • hartnn
right,so thats 21x^2-40x-21=0 right ?
anonymous
  • anonymous
yeah and then the product of 21 and -21 is -441 and then 40 so the two numbers are -49 and 9
hartnn
  • hartnn
that is correct, see above u have written -49x - 9x instead of what u got now as -49x+9x
anonymous
  • anonymous
oooh i see wow
hartnn
  • hartnn
now whats common from first 2 terms in 21x^2-49x-9x-21 =0?
anonymous
  • anonymous
7x
anonymous
  • anonymous
i got the answer :P -3/7 and 7/3
hartnn
  • hartnn
yup, correct.
anonymous
  • anonymous
im having problems with another equation
hartnn
  • hartnn
which ?
anonymous
  • anonymous
anonymous
  • anonymous
i got to the point 9 + or - sqrt of 1 all over 4
hartnn
  • hartnn
9 from where ?
hartnn
  • hartnn
Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two rots of x are: \(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
anonymous
  • anonymous
yeah b is 9
hartnn
  • hartnn
nopes, b is -4
anonymous
  • anonymous
oh wait nooo i gave you the wrong equation! no wonder
hartnn
  • hartnn
lol :P
anonymous
  • anonymous
hartnn
  • hartnn
still b is -9
anonymous
  • anonymous
but in that equation it says -b so -(-9) is 9
anonymous
  • anonymous
inside i did put put -9^2 = 81
hartnn
  • hartnn
yes, u are correct \(\huge\frac{9 \pm \sqrt{1}}{4}=\frac{10}{4},\frac{8}{4}\)
anonymous
  • anonymous
wait you are just adding and subtracting the 1?
anonymous
  • anonymous
obviously lol never mind i feel stupid
hartnn
  • hartnn
got it now ?
anonymous
  • anonymous
yes, it was a stupid moment :P
anonymous
  • anonymous
ok i did another one and i got 4+-sqrt of 28 all over 2 @hartnn
hartnn
  • hartnn
question ?
anonymous
  • anonymous
its the first one that sent you
anonymous
  • anonymous
hartnn
  • hartnn
thats correct :)
anonymous
  • anonymous
but how do i factor it?
hartnn
  • hartnn
do u want to factor or do u want to use quadratic formula? anyways its not factorable....
anonymous
  • anonymous
so what would be the answer?
anonymous
  • anonymous
i cant simplify it?
hartnn
  • hartnn
all u can do is \(2 \pm \sqrt7\)
hartnn
  • hartnn
\(\sqrt{28}=2\sqrt7\)
anonymous
  • anonymous
how does that equal to that
hartnn
  • hartnn
\(\sqrt{28}=\sqrt{7*4}=\sqrt{7}\sqrt{4}=2\sqrt{7}\)
anonymous
  • anonymous
got it
anonymous
  • anonymous
you are the best!
hartnn
  • hartnn
lol. glad to hear that :) u too are awesome ;)
anonymous
  • anonymous
lol thank you, well i gotta keep doing this stupid hw
hartnn
  • hartnn
best of luck for that.

Looking for something else?

Not the answer you are looking for? Search for more explanations.