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Mimi_x3Best ResponseYou've already chosen the best response.0
dw:1347405240429:dw hopefully you can understand that..
 one year ago

zzr0ck3rBest ResponseYou've already chosen the best response.0
note at all, I want get from the first one to the second one, say I was given to2x^33x+1, how do I get to (x1)(2x^2+2x1). I dont see how what you did applies
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
there is an alternative way:\[\begin{align} 2x^33x+1&=x(2x^23)+1\\ &=x(2x^23)(2x^23)+(2x^23)+1\\ &=(x1)(2x^23)+2x^23+1\\ &=(x1)(2x^23)+2x^22\\ &=(x1)(2x^23)+2(x^21)\\ &=(x1)(2x^23)+2(x1)(x+1)\\ &=(x1)(2x^23+2(x+1))\\ &=(x1)(2x^23+2x+2)\\ &=(x1)(2x^2+2x1) \end{align}\]
 one year ago

zzr0ck3rBest ResponseYou've already chosen the best response.0
this is all to see where 2x^33x+1>0
 one year ago
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