Hi again... what class is this for?
I'm away from anything that I could quickly reference for the regression model it mentions...
You can consider part b for a moment though... Slope is how fast the ticket price seems to be increasing (or decreasing, but it appears to be going up here) each year. Just like slope says how much increase in y for each step of x
The regression model should give you the line expression, as I recall... so you could "plug in" 2013 to get part c. You need to consider each of the years as the time since 2000, so you end up with small numbers like 7, 8, etc, not big like 2007, etc. So you could plug in "13" to get part c
Okay, Anything else?
Do you have anything to go on for the linear regression method? Is it an Excel project, or something to calculate by hand, or any idea? It looks possible but time consuming to do manually.
I have no idea actually. That's alright. I'll try it somehow. Can you help me with two more problems?
Maybe, gotta run in a minute, but I might be back on later. Give me one or both, I'll see...
So, for 2, "varies directly" means linearly, so it's like an equation of a line. W is a function of S, but you don't know the slope or how MUCH it varies. so W(S) is proportional to S, or W(S) = mS + b, where m is the unknown slope and b is the unknown intercept
oh, wait... they use k as the constant, and they ignore the intercept So, it's W(S) = kS
So, sub in the values they give you for W and S in part (b) and solve for the k term. In (c), rewrite the W(S) function using the actual constant k from part (b) and sub in S=175 as given
The other problem just looks like a little basic simplifying of one equation, then some graphing on the calculator. Also, maybe your calculator has a linear regression tool built in that could help on that first one... something where you enter the years (remember, 7, 8, 9, etc not 2007, etc) and the ticket prices and it produces the regression model which is the expression for the line. Something to look for, maybe...