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An electron enters midway through a uniform electric field of 198 N/C at an initial velocity of 416 m/s, as shown in the diagram. If the plates are separated by a distance of 2.02 cm, how far along the xaxis will the electron hit the bottom plate.
 one year ago
 one year ago
An electron enters midway through a uniform electric field of 198 N/C at an initial velocity of 416 m/s, as shown in the diagram. If the plates are separated by a distance of 2.02 cm, how far along the xaxis will the electron hit the bottom plate.
 one year ago
 one year ago

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nj1202Best ResponseYou've already chosen the best response.0
I have an anwer, but for some reason i'm feeling it doesn't make sense... and that's not good cuz i'm learning this too and i can't even remember how exactly xD
 one year ago

jatasiaBest ResponseYou've already chosen the best response.0
well any help is fine with me :)
 one year ago

jatasiaBest ResponseYou've already chosen the best response.0
oh i see do i have to convert any numbers
 one year ago

nj1202Best ResponseYou've already chosen the best response.0
Well everything seems alright as given. But i just ran another vertical displacement equation and if we substitute in the horizontal d i just found above, it doesn't reach the plate... so the above is not correct..
 one year ago

jatasiaBest ResponseYou've already chosen the best response.0
yeah i tried it out :(
 one year ago

nj1202Best ResponseYou've already chosen the best response.0
Is this like an online thing where it tells you if you're right?
 one year ago

nj1202Best ResponseYou've already chosen the best response.0
okay, well let's work through this, it'll help us both. First we should find the acceleration of the electron, obviously in the y direction.
 one year ago

jatasiaBest ResponseYou've already chosen the best response.0
would we do the same for the x
 one year ago

nj1202Best ResponseYou've already chosen the best response.0
Not necessary i don't think. the particle will move at constant velocity forever in the horizontal, so i think we just need vertical here. now we need the time to get a position.
 one year ago

nj1202Best ResponseYou've already chosen the best response.0
i think this might be right xD but check it out.
 one year ago

jatasiaBest ResponseYou've already chosen the best response.0
oh ok... and nope im not sure exactly whats not adding up though
 one year ago

nj1202Best ResponseYou've already chosen the best response.0
I don't know.. i followed what i think i'd do. idk what else to try xD
 one year ago

jatasiaBest ResponseYou've already chosen the best response.0
me neither suppose im hopeless lol
 one year ago
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