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lynn555
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consider the point (x,y) lying on the graph of y=(x+3)^1/2. let L be the distance between the points (x,y) and (4,0). write l as a function of y
 one year ago
 one year ago
lynn555 Group Title
consider the point (x,y) lying on the graph of y=(x+3)^1/2. let L be the distance between the points (x,y) and (4,0). write l as a function of y
 one year ago
 one year ago

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Jemurray3 Group TitleBest ResponseYou've already chosen the best response.2
\[L = \sqrt{ (x4)^2 + y^2 } \] and \[ y = \sqrt{x+3} \implies x = y^2  3\] so substitute that in.
 one year ago

lynn555 Group TitleBest ResponseYou've already chosen the best response.0
so the answer would be y^546+x?
 one year ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.2
erm, no. Literally substitute y^23 in for x in the equation that starts with L = ...
 one year ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.2
there should be no x involved.
 one year ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
dw:1347425169078:dw
 one year ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
so given function is y=(x+3)^1/2 so y^2=x+3, so, x = y^23. plugging x to the L=(x4)^2 + y^2 then, L=(y^26)^2 + y^2
 one year ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
you can reduce it easily
 one year ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.2
That should be y^27, not y^26, and the whole thing should be under a square root. But yeah.
 one year ago
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