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ebydaqueen17
Group Title
SOLVE INEQUALITY
0 is less than or equal to 3(u4) over 7 which is less than or equal to 1
 2 years ago
 2 years ago
ebydaqueen17 Group Title
SOLVE INEQUALITY 0 is less than or equal to 3(u4) over 7 which is less than or equal to 1
 2 years ago
 2 years ago

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telltoamit Group TitleBest ResponseYou've already chosen the best response.1
u can treat them like equations except that u never multiply wid a negative number
 2 years ago

ebydaqueen17 Group TitleBest ResponseYou've already chosen the best response.1
dw:1347429316540:dw
 2 years ago

ebydaqueen17 Group TitleBest ResponseYou've already chosen the best response.1
Could you tell me what number to multiply with?
 2 years ago

telltoamit Group TitleBest ResponseYou've already chosen the best response.1
multiply by 7
 2 years ago

ebydaqueen17 Group TitleBest ResponseYou've already chosen the best response.1
ok thanks....
 2 years ago

ebydaqueen17 Group TitleBest ResponseYou've already chosen the best response.1
dw:1347429626034:dw
 2 years ago

ebydaqueen17 Group TitleBest ResponseYou've already chosen the best response.1
is tht how its supposed to look?
 2 years ago

telltoamit Group TitleBest ResponseYou've already chosen the best response.1
dw:1347429751810:dw
 2 years ago

ebydaqueen17 Group TitleBest ResponseYou've already chosen the best response.1
i got it thanks
 2 years ago

TAKEBACKMATH Group TitleBest ResponseYou've already chosen the best response.0
yes now add 12 to all three sides getting \[12\le 3v \le 19\]
 2 years ago

ebydaqueen17 Group TitleBest ResponseYou've already chosen the best response.1
got it...thanks
 2 years ago

TAKEBACKMATH Group TitleBest ResponseYou've already chosen the best response.0
oh wait that a 1 not a 7
 2 years ago

ebydaqueen17 Group TitleBest ResponseYou've already chosen the best response.1
its okay i alreddi got the answer..
 2 years ago

TAKEBACKMATH Group TitleBest ResponseYou've already chosen the best response.0
now divide by 3 on all three sides \[4 \le v \le \frac{ 13 }{3 }\]
 2 years ago

TAKEBACKMATH Group TitleBest ResponseYou've already chosen the best response.0
oh okay
 2 years ago
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