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Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
\[\int \frac{(x+2)^2}{x}dx\]
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
maybe usub
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
Expand (x+2)^2 (a+b)^2 = a^2+2ab+b^2
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
yeah; and break it into fractions, easier!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
@ieatpi can u ?
 one year ago

ieatpi Group TitleBest ResponseYou've already chosen the best response.0
I don't think we've learned that yet
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
what have you learnt
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
u haven't learnt (a+b)^2 ??
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
you're too advanced @hartnn
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
well for those who started calculus , (a+b)^2 isn't advanced.
 one year ago

ieatpi Group TitleBest ResponseYou've already chosen the best response.0
ok so \[\int\limits_{}^{}(x^{2}+4x + 4)/ x\], now what?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
you don't know online schools then @hartnn
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
lol an advanced method is to use usub and long division; for this question igba :P
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
then break it into fractions!
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
\[\int\limits\frac{x^{2}+4x+4}{x} => \int\limits\frac{x^{2}}{x} +\frac{4x}{x} +\frac{4}{x} \]
 one year ago

ieatpi Group TitleBest ResponseYou've already chosen the best response.0
omg, I'm an idiot
 one year ago

ieatpi Group TitleBest ResponseYou've already chosen the best response.0
lol thanks guys
 one year ago
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