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gaurangnaware

integration of "e" raise to power "x" square

  • one year ago
  • one year ago

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  1. lgbasallote
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    \[\huge \int e^{x^2}dx\] ???

    • one year ago
  2. lgbasallote
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    is that your question?

    • one year ago
  3. gaurangnaware
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    yes

    • one year ago
  4. lgbasallote
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    ..this isn't solveable by natural means...

    • one year ago
  5. gaurangnaware
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    well how do i slove it?

    • one year ago
  6. lgbasallote
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    numerical analysis was the term if i remember it right

    • one year ago
  7. gaurangnaware
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    erf...?

    • one year ago
  8. lgbasallote
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    yup. those kinds of functions

    • one year ago
  9. lgbasallote
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    only mathematicians solve this. Because they love solving imaginary problems.

    • one year ago
  10. gaurangnaware
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    well i am solving an ode and the question is if the given y satisfies it and it contains.. inte^x^2...

    • one year ago
  11. lgbasallote
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    they give these stuffs in ode now? are you by any chance from a premier university?

    • one year ago
  12. gaurangnaware
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    haha well Ph.D.. i have forgotten the basics.. was just revising

    • one year ago
  13. Algebraic!
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    http://www.wolframalpha.com/input/?i=error+function&dataset=&asynchronous=false&equal=Submit

    • one year ago
  14. mukushla
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    http://www.wolframalpha.com/input/?i=integrate+e^%28x^2%29 imaginary error function !!

    • one year ago
  15. lgbasallote
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    I am a PhD myself. However, I'm from Liberal Arts...

    • one year ago
  16. Algebraic!
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    @mukushla jinx

    • one year ago
  17. lgbasallote
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    i think @gaurangnaware wants to know how to get that erf function....

    • one year ago
  18. mukushla
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    lol Algebraic

    • one year ago
  19. myko
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    use series

    • one year ago
  20. gaurangnaware
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    Thanx Mukushla.. go it!

    • one year ago
  21. mukushla
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    no problem :)

    • one year ago
  22. myko
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    series expantion of ex2 is: \[e ^{x ^{2}}=1+\frac{x ^{2}}{1!}+\frac{x ^{4}}{2!}+\frac{x ^{6}}{3!}+....\] this is a uniformly convergent series, so you can integrate it term by term. So just integrate each term to get your answer.

    • one year ago
  23. myko
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    @gaurangnaware

    • one year ago
  24. myko
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    @lgbasallote

    • one year ago
  25. heedcom
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    or use polar

    • one year ago
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