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anonymous
 4 years ago
find the derivative of y=(x²+51/x²)²
my steps:
y'=2[x²+5x^(2)](2x+2x)
=4x³+20x4x^(1)
but the answer given is 4x³+20x+20/x³4/x^5
why am i wrong?
anonymous
 4 years ago
find the derivative of y=(x²+51/x²)² my steps: y'=2[x²+5x^(2)](2x+2x) =4x³+20x4x^(1) but the answer given is 4x³+20x+20/x³4/x^5 why am i wrong?

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Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.0\[y=\left(\frac{x^{2}+51}{x^{2}}\right)^{2} \]??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x^2+5\frac{1}{x^2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your step was wrong.. at first

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well one minor mistake

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what have i done wrong?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is derivative of y = (x^2 + 5  1)^2 * (x^2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the derivative of x^(2) is not 2x it's 2x^3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so just change your 2x there with 2x^3 and you're fine. redo the rest of the solution

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so you use if y = fg y' = f'g + fg'

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lgbasallote, i get it, thanks!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0welcome. also...don't forget you still have a 2 outside..you have to distribute it to the equation too

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0try use chain rule to solve it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the eq is not a ratio..
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