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startanewww

  • 2 years ago

find the derivative of y=(x²+5-1/x²)² my steps: y'=2[x²+5-x^(-2)](2x+2x) =4x³+20x-4x^(-1) but the answer given is 4x³+20x+20/x³-4/x^5 why am i wrong?

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  1. Mimi_x3
    • 2 years ago
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    \[y=\left(\frac{x^{2}+5-1}{x^{2}}\right)^{2} \]??

  2. mukushla
    • 2 years ago
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    \[x^2+5-\frac{1}{x^2}\]

  3. LeeYeongKyu
    • 2 years ago
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    your step was wrong.. at first

  4. startanewww
    • 2 years ago
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    why?

  5. lgbasallote
    • 2 years ago
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    he's right....

  6. lgbasallote
    • 2 years ago
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    well one minor mistake

  7. startanewww
    • 2 years ago
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    what have i done wrong?

  8. LeeYeongKyu
    • 2 years ago
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    it is derivative of y = (x^2 + 5 - 1)^2 * (x^-2)

  9. lgbasallote
    • 2 years ago
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    the derivative of x^(-2) is not -2x it's -2x^-3

  10. lgbasallote
    • 2 years ago
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    so just change your 2x there with 2x^-3 and you're fine. redo the rest of the solution

  11. LeeYeongKyu
    • 2 years ago
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    so you use if y = fg y' = f'g + fg'

  12. startanewww
    • 2 years ago
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    lgbasallote, i get it, thanks!

  13. lgbasallote
    • 2 years ago
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    welcome. also...don't forget you still have a 2 outside..you have to distribute it to the equation too

  14. meer1992
    • 2 years ago
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    try use chain rule to solve it

  15. LeeYeongKyu
    • 2 years ago
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    the eq is not a ratio..

  16. LeeYeongKyu
    • 2 years ago
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    damn..

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