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startanewww
Group Title
find the derivative of y=(x²+51/x²)²
my steps:
y'=2[x²+5x^(2)](2x+2x)
=4x³+20x4x^(1)
but the answer given is 4x³+20x+20/x³4/x^5
why am i wrong?
 one year ago
 one year ago
startanewww Group Title
find the derivative of y=(x²+51/x²)² my steps: y'=2[x²+5x^(2)](2x+2x) =4x³+20x4x^(1) but the answer given is 4x³+20x+20/x³4/x^5 why am i wrong?
 one year ago
 one year ago

This Question is Closed

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
\[y=\left(\frac{x^{2}+51}{x^{2}}\right)^{2} \]??
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
\[x^2+5\frac{1}{x^2}\]
 one year ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
your step was wrong.. at first
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
he's right....
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
well one minor mistake
 one year ago

startanewww Group TitleBest ResponseYou've already chosen the best response.1
what have i done wrong?
 one year ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
it is derivative of y = (x^2 + 5  1)^2 * (x^2)
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
the derivative of x^(2) is not 2x it's 2x^3
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
so just change your 2x there with 2x^3 and you're fine. redo the rest of the solution
 one year ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
so you use if y = fg y' = f'g + fg'
 one year ago

startanewww Group TitleBest ResponseYou've already chosen the best response.1
lgbasallote, i get it, thanks!
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
welcome. also...don't forget you still have a 2 outside..you have to distribute it to the equation too
 one year ago

meer1992 Group TitleBest ResponseYou've already chosen the best response.0
try use chain rule to solve it
 one year ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
the eq is not a ratio..
 one year ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
damn..
 one year ago
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