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startanewww
Group Title
find the derivative of y=(x²+51/x²)²
my steps:
y'=2[x²+5x^(2)](2x+2x)
=4x³+20x4x^(1)
but the answer given is 4x³+20x+20/x³4/x^5
why am i wrong?
 2 years ago
 2 years ago
startanewww Group Title
find the derivative of y=(x²+51/x²)² my steps: y'=2[x²+5x^(2)](2x+2x) =4x³+20x4x^(1) but the answer given is 4x³+20x+20/x³4/x^5 why am i wrong?
 2 years ago
 2 years ago

This Question is Closed

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
\[y=\left(\frac{x^{2}+51}{x^{2}}\right)^{2} \]??
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
\[x^2+5\frac{1}{x^2}\]
 2 years ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
your step was wrong.. at first
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
he's right....
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
well one minor mistake
 2 years ago

startanewww Group TitleBest ResponseYou've already chosen the best response.1
what have i done wrong?
 2 years ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
it is derivative of y = (x^2 + 5  1)^2 * (x^2)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
the derivative of x^(2) is not 2x it's 2x^3
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
so just change your 2x there with 2x^3 and you're fine. redo the rest of the solution
 2 years ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
so you use if y = fg y' = f'g + fg'
 2 years ago

startanewww Group TitleBest ResponseYou've already chosen the best response.1
lgbasallote, i get it, thanks!
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
welcome. also...don't forget you still have a 2 outside..you have to distribute it to the equation too
 2 years ago

meer1992 Group TitleBest ResponseYou've already chosen the best response.0
try use chain rule to solve it
 2 years ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
the eq is not a ratio..
 2 years ago
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