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startanewww Group Title

find the derivative of y=(x²+5-1/x²)² my steps: y'=2[x²+5-x^(-2)](2x+2x) =4x³+20x-4x^(-1) but the answer given is 4x³+20x+20/x³-4/x^5 why am i wrong?

  • one year ago
  • one year ago

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  1. Mimi_x3 Group Title
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    \[y=\left(\frac{x^{2}+5-1}{x^{2}}\right)^{2} \]??

    • one year ago
  2. mukushla Group Title
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    \[x^2+5-\frac{1}{x^2}\]

    • one year ago
  3. LeeYeongKyu Group Title
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    your step was wrong.. at first

    • one year ago
  4. startanewww Group Title
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    why?

    • one year ago
  5. lgbasallote Group Title
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    he's right....

    • one year ago
  6. lgbasallote Group Title
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    well one minor mistake

    • one year ago
  7. startanewww Group Title
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    what have i done wrong?

    • one year ago
  8. LeeYeongKyu Group Title
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    it is derivative of y = (x^2 + 5 - 1)^2 * (x^-2)

    • one year ago
  9. lgbasallote Group Title
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    the derivative of x^(-2) is not -2x it's -2x^-3

    • one year ago
  10. lgbasallote Group Title
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    so just change your 2x there with 2x^-3 and you're fine. redo the rest of the solution

    • one year ago
  11. LeeYeongKyu Group Title
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    so you use if y = fg y' = f'g + fg'

    • one year ago
  12. startanewww Group Title
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    lgbasallote, i get it, thanks!

    • one year ago
  13. lgbasallote Group Title
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    welcome. also...don't forget you still have a 2 outside..you have to distribute it to the equation too

    • one year ago
  14. meer1992 Group Title
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    try use chain rule to solve it

    • one year ago
  15. LeeYeongKyu Group Title
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    the eq is not a ratio..

    • one year ago
  16. LeeYeongKyu Group Title
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    damn..

    • one year ago
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