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find the derivative of y=(x²+5-1/x²)² my steps: y'=2[x²+5-x^(-2)](2x+2x) =4x³+20x-4x^(-1) but the answer given is 4x³+20x+20/x³-4/x^5 why am i wrong?

Mathematics
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\[y=\left(\frac{x^{2}+5-1}{x^{2}}\right)^{2} \]??
\[x^2+5-\frac{1}{x^2}\]
your step was wrong.. at first

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Other answers:

why?
he's right....
well one minor mistake
what have i done wrong?
it is derivative of y = (x^2 + 5 - 1)^2 * (x^-2)
the derivative of x^(-2) is not -2x it's -2x^-3
so just change your 2x there with 2x^-3 and you're fine. redo the rest of the solution
so you use if y = fg y' = f'g + fg'
lgbasallote, i get it, thanks!
welcome. also...don't forget you still have a 2 outside..you have to distribute it to the equation too
try use chain rule to solve it
the eq is not a ratio..
damn..

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