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apple_pi Group Title

The parabola y=ax^2+bx+c, c≠0 meets the x-axis at A(α,0) and B(β,0) and the y-axis at C. If AC and BC are perpendicular, prove ac=-1

  • 2 years ago
  • 2 years ago

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  1. apple_pi Group Title
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    @lgbasallote

    • 2 years ago
  2. akash123 Group Title
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    alpha and beta are the roots of quadratic ax^2+bx+c=0

    • 2 years ago
  3. akash123 Group Title
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    so alpha + beta = -b/a and alpha* beta= c/a

    • 2 years ago
  4. lgbasallote Group Title
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    sure...tag the math hater to a math problem...makes a lot of sense

    • 2 years ago
  5. akash123 Group Title
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    slope of AC * slope of BC= -1

    • 2 years ago
  6. akash123 Group Title
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    so alpha* beta = -c^2

    • 2 years ago
  7. akash123 Group Title
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    and put this value into... alpha* beta= c/a

    • 2 years ago
  8. akash123 Group Title
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    so ac=-1

    • 2 years ago
  9. akash123 Group Title
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    does it make sense?

    • 2 years ago
  10. apple_pi Group Title
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    how did you get to alpha*beta=-c^2?

    • 2 years ago
  11. akash123 Group Title
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    use this...slope of AC * slope of BC= -1 c=(0, beta)

    • 2 years ago
  12. mathslover Group Title
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    No one tags mathslover though :P

    • 2 years ago
  13. apple_pi Group Title
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    since when does c=(0,beta)?

    • 2 years ago
  14. akash123 Group Title
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    so slope of AC= - c/alpha=m1 , slope of BC= -c/beta=m2 m1 *m2= -1...since AC is perpendicular to BC.

    • 2 years ago
  15. akash123 Group Title
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    sorry C=(0,c)

    • 2 years ago
  16. apple_pi Group Title
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    right

    • 2 years ago
  17. apple_pi Group Title
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    @akash123 @ganeshie8

    • 2 years ago
  18. akash123 Group Title
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    u got it?

    • 2 years ago
  19. apple_pi Group Title
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    yah

    • 2 years ago
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