A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
The parabola y=ax^2+bx+c, c≠0 meets the xaxis at A(α,0) and B(β,0) and the yaxis at C. If AC and BC are perpendicular, prove ac=1
anonymous
 4 years ago
The parabola y=ax^2+bx+c, c≠0 meets the xaxis at A(α,0) and B(β,0) and the yaxis at C. If AC and BC are perpendicular, prove ac=1

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alpha and beta are the roots of quadratic ax^2+bx+c=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so alpha + beta = b/a and alpha* beta= c/a

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1sure...tag the math hater to a math problem...makes a lot of sense

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0slope of AC * slope of BC= 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so alpha* beta = c^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and put this value into... alpha* beta= c/a

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you get to alpha*beta=c^2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0use this...slope of AC * slope of BC= 1 c=(0, beta)

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.0No one tags mathslover though :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0since when does c=(0,beta)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so slope of AC=  c/alpha=m1 , slope of BC= c/beta=m2 m1 *m2= 1...since AC is perpendicular to BC.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.