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anonymous
 4 years ago
The parabola y=ax^2+bx+c, c≠0 meets the xaxis at A(α,0) and B(β,0) and the yaxis at C. If AC and BC are perpendicular, prove ac=1
anonymous
 4 years ago
The parabola y=ax^2+bx+c, c≠0 meets the xaxis at A(α,0) and B(β,0) and the yaxis at C. If AC and BC are perpendicular, prove ac=1

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alpha and beta are the roots of quadratic ax^2+bx+c=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so alpha + beta = b/a and alpha* beta= c/a

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sure...tag the math hater to a math problem...makes a lot of sense

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0slope of AC * slope of BC= 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so alpha* beta = c^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and put this value into... alpha* beta= c/a

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you get to alpha*beta=c^2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0use this...slope of AC * slope of BC= 1 c=(0, beta)

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.0No one tags mathslover though :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0since when does c=(0,beta)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so slope of AC=  c/alpha=m1 , slope of BC= c/beta=m2 m1 *m2= 1...since AC is perpendicular to BC.
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