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\[\frac{ t^2+6t }{ t-1 }-\frac{7}{t-1}=\frac{ t^2+6t - 7}{ t-1 }=\frac{(t-1)(t+6)}{t-1}=t+6\]

why dont i factor t out?

ok so for example \[[(4x+4)/(x(x+1)]-[(11x)/(x(x+1)] is then [(4x+4-11x)/(x(x+1)]\]

what did u you to write like that?

yes, and you have a quadratic in the numerator and factor this to cancel with the denominator

press the equation button just under the bit where you reply

so its (4-7x)/(x(x+1))

i tried that and it doesnt look like that on my screen

Bottom left of screenshot. Press this then enter equation