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jukeu2buhu

  • 3 years ago

Im trying to finish an assignment, but learning this section is online is a little difficult, can someone help me? The first question asks me to simplify [(t^2+6t)/(t-1)]-[(7)/(t-1)] and I've simplified it to [(t(t+6))/(t-1)]+[(-7)/(t-1)] but I dont know what to do here. I have common denominators and I think I can cancel t out from the left left side problem from the top and bottom but Im not sure. Help please?

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  1. jukeu2buhu
    • 3 years ago
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    |dw:1347446293115:dw|

  2. apple_pi
    • 3 years ago
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    \[\frac{ t^2+6t }{ t-1 }-\frac{7}{t-1}=\frac{ t^2+6t - 7}{ t-1 }=\frac{(t-1)(t+6)}{t-1}=t+6\]

  3. jukeu2buhu
    • 3 years ago
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    why dont i factor t out?

  4. apple_pi
    • 3 years ago
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    you could, but that wouldn't do anything. You have yourself a quadratic in the numerator, so just factor the whole thing. That way the denominator cancels out

  5. jukeu2buhu
    • 3 years ago
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    ok so for example \[[(4x+4)/(x(x+1)]-[(11x)/(x(x+1)] is then [(4x+4-11x)/(x(x+1)]\]

  6. jukeu2buhu
    • 3 years ago
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    what did u you to write like that?

  7. apple_pi
    • 3 years ago
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    yes, and you have a quadratic in the numerator and factor this to cancel with the denominator

  8. apple_pi
    • 3 years ago
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    press the equation button just under the bit where you reply

  9. jukeu2buhu
    • 3 years ago
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    so its (4-7x)/(x(x+1))

  10. jukeu2buhu
    • 3 years ago
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    i tried that and it doesnt look like that on my screen

  11. apple_pi
    • 3 years ago
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    Bottom left of screenshot. Press this then enter equation

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