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apple_piBest ResponseYou've already chosen the best response.0
differentiate each and equate the derivatives
 one year ago

apple_piBest ResponseYou've already chosen the best response.0
woah @akash123 where'd that come from?
 one year ago

akash123Best ResponseYou've already chosen the best response.1
differentiate each and equate the derivatives
 one year ago

apple_piBest ResponseYou've already chosen the best response.0
You were scaring me there
 one year ago

apple_piBest ResponseYou've already chosen the best response.0
@JJ1371 taking it in...
 one year ago

akash123Best ResponseYou've already chosen the best response.1
where? proving the collinearity..
 one year ago

apple_piBest ResponseYou've already chosen the best response.0
no, just suddenly pulling an answer
 one year ago

JJ1371Best ResponseYou've already chosen the best response.0
sorry, the second y=x^3
 one year ago

apple_piBest ResponseYou've already chosen the best response.0
Ok, follow the procedure
 one year ago

JJ1371Best ResponseYou've already chosen the best response.0
y=1+2x y=2x^2 1+2x = 2x^2 where to now?
 one year ago

akash123Best ResponseYou've already chosen the best response.1
now u have to solve this quadratic equation and find the values of x
 one year ago

akash123Best ResponseYou've already chosen the best response.1
derivative of x^3 = 3 x^2
 one year ago

akash123Best ResponseYou've already chosen the best response.1
derivative of x^n = n x^(n1)
 one year ago

JJ1371Best ResponseYou've already chosen the best response.0
3x^2  2x 1 = 0 Quadratic equation?
 one year ago

JJ1371Best ResponseYou've already chosen the best response.0
therefore x = 3 or x = 1?
 one year ago

akash123Best ResponseYou've already chosen the best response.1
no...3x^2  2x 1 = 0 =(x3)(x+1) is wrong do the factorization again
 one year ago
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