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akash123 Group TitleBest ResponseYou've already chosen the best response.0
range of cos ?
 2 years ago

akash123 Group TitleBest ResponseYou've already chosen the best response.0
i mean what's the max and min of cos x?
 2 years ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.0
I think hes asking if its asked for an interval or the whole function. Because if there are no interval than the domain of cosine is for all real numbers
 2 years ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.0
and yoru range is between 0 and pi (so 0<=y<=pi)
 2 years ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.0
and for hte domain it is  sqrt(2) <=x<=sqrt(2)
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.0
@MarcLeclair may you please show me how to do it?
 2 years ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.0
yes give me one second :)
 2 years ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.0
did your teacher giove you the domain of the arccosine function?
 2 years ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.0
There is a set one but im just wondering if you have it
 2 years ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.0
dw:1347453496255:dwOkay so the arccosine function has ( INITIALLY) a domain of 1<=x<=1 and a range of 0<=y<=pi this is because the graph of a arccos is mor vertical, if we ake a range or domain bigger than that it loses its role of function as one x has more than one image
 2 years ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.0
however, the function youve asked for has been shifted. Therefore, you have to solve for not arccosine X but arcossine x^21. for the domain you do as follow 1<= (x^2+1)<= 1
 2 years ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.0
same goes for the range, you hae 0<=y<=pi, then you have to insert your function so : 0<= arccosin (x^2+1)<=0 You then have to solve forthe inequality :D
 2 years ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.0
hope it helped if you need help wit hthe inequalities I will :)
 2 years ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.0
0<= arccosin (x^2+1)<=pi*
 2 years ago
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