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Use ∆ABC to answer the question that follows.
Given: ∆ABC
Prove: The three medians of ∆ABC intersect at a common point.
When written in the correct order, the twocolumn proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point.
Which is the most logical order of statements and justifications I, II, III, and IV to complete the proof?
 one year ago
 one year ago
Use ∆ABC to answer the question that follows. Given: ∆ABC Prove: The three medians of ∆ABC intersect at a common point. When written in the correct order, the twocolumn proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point. Which is the most logical order of statements and justifications I, II, III, and IV to complete the proof?
 one year ago
 one year ago

This Question is Closed

BIGDOG96Best ResponseYou've already chosen the best response.1
Statements Justifications Point F is a midpoint of Line segment AB Point E is a midpoint of Line segment AC Draw Line segment BE Draw Line segment FC by Construction Point G is the point of intersection between Line segment BE and Line segment FC Intersecting Lines Postulate Draw Line segment AG by Construction Point D is the point of intersection between Line segment AG and Line segment BC Intersecting Lines Postulate Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH by Construction I BGCH is a parallelogram Properties of a Parallelogram (opposite sides are parallel) II Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC Midsegment Theorem III Line segment BD ≅ Line segment DC Properties of a Parallelogram (diagonals bisect each other) IV Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC Substitution Line segment AD is a median Definition of a Median
 one year ago

BIGDOG96Best ResponseYou've already chosen the best response.1
IV, II, III, I II, IV, I, III IV, II, I, III II, IV, III, I
 one year ago

BIGDOG96Best ResponseYou've already chosen the best response.1
It won't let me post the statements and justification in a two column
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
try taking a screenshot and post the pix... here you're trying to use parallelogram properties i think
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
look at \(\triangle ABH\)
 one year ago

BIGDOG96Best ResponseYou've already chosen the best response.1
Just heads up I HAVE NO CLUE what I'm doing.
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
FG is the midsegment , so it is parallel to BH FG  BH
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
its okay im sure you would get enough clue by the time we finish ;p
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
do the same thing for another triangle, look at \(\triangle\) AHC whats the midsegment in that triangle
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1347462588707:dw
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1347462742317:dw
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
thats right, EG is the midsegment
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
good work :) so far. so our first statement must be which one ?
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
lets continue our logic from this point
 one year ago

BIGDOG96Best ResponseYou've already chosen the best response.1
There's only two that start with two.
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
only one of them is true
 one year ago

BIGDOG96Best ResponseYou've already chosen the best response.1
And they both have four next
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
we have this so far : we got two parallel sides according to midsegment theorem : FG  BH GE  HC
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1347463059283:dw
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
since GE  HC, BG also parallel to HC BG  HC so next statement is IV as you said
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
what could be the next ?
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1347463185726:dw
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
thats one set of parallel sides
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1347463228999:dw
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
thats another set of parallel sides
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
doesnt it make that piece a parallelogram ?
 one year ago

BIGDOG96Best ResponseYou've already chosen the best response.1
So I was right, it's 1?
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
yes ofcourse you're right :)
 one year ago

BIGDOG96Best ResponseYou've already chosen the best response.1
See you later. Thanks again!
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
is that a smiley D or you're saying the correct sequence is D lol
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
the correct sequence of statements is this : II, IV, I, III
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
good luck wid ur geometry proofs looks like you're at end of course. wish u best grades :) cya
 one year ago
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