Amy876
3. The sum of three consecutive even integers is 84. What is the least of these numbers?
(Points : 1)
-34
-30
-26
30
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dpaInc
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let x be the least of these numbers... since they're consecutive, the next one would be (x+2), and the next one after that is (x+4)...
since their sum is 84, you can write it out as:
x + (x+2) + (x+4) = 84
now all u gotta do is solve....
Amy876
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How do I solve that???
Nameless
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combine like terms and isolate x
Amy876
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I dont know how to do that
Nameless
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x + x + x are all the same.. so add them up = 3x... same with the 4 2
Nameless
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now you should have 3x + 6 = 84. now you want your x term on one side of the equation and the numbers on the other side.
Amy876
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is it 18?
Nameless
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subtract 6 from both sides... thus 3x + 6 - 6 = 84 - 6
Nameless
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so 3x = 78. now you need to get rid of that 3.
Amy876
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How?
Nameless
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you can divide by the coefficient of x.. in this case 3. thus 3x/3 = 78/3
Nameless
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that will give you x = the result of 78/3
Amy876
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26? :)
Amy876
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oh wait -26?
Nameless
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yep.. now check.. 26, + 28 + 30?
Nameless
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i dont think someone can be negative years old.
Amy876
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positive 26 is NOT an option :(
Amy876
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what?
Nameless
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ooh i thought it was an age question. sorry
Amy876
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its ok :/
Nameless
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all those negatives dont make any sense...it is .. i think.. impossible for you to take a negative number with 3 consecutive even integers and add them up to 24.
Nameless
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and 30 doesnt work
Amy876
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Nope it was 30
Amy876
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I just got the answers
Nameless
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30+32+34 is 96?
Nameless
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good luck
Amy876
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thanks
dpaInc
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30 + 32 + 34 \(\large \ne 84\) so the answer cannot be 30....
the answer to your question is 26...
26 + 28 + 30 = 84
looks like the correct choice is not there or the problem was mistyped...
this is your orginal question:
3. The sum of three consecutive even integers is 84. What is the least of these numbers?
(Points : 1)
-34
-30
-26
30