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let x be the least of these numbers... since they're consecutive, the next one would be (x+2), and the next one after that is (x+4)... since their sum is 84, you can write it out as: x + (x+2) + (x+4) = 84 now all u gotta do is solve....
How do I solve that???
combine like terms and isolate x
I dont know how to do that
x + x + x are all the same.. so add them up = 3x... same with the 4 2
now you should have 3x + 6 = 84. now you want your x term on one side of the equation and the numbers on the other side.
is it 18?
subtract 6 from both sides... thus 3x + 6 - 6 = 84 - 6
so 3x = 78. now you need to get rid of that 3.
you can divide by the coefficient of x.. in this case 3. thus 3x/3 = 78/3
that will give you x = the result of 78/3
oh wait -26?
yep.. now check.. 26, + 28 + 30?
i dont think someone can be negative years old.
positive 26 is NOT an option :(
ooh i thought it was an age question. sorry
its ok :/
all those negatives dont make any sense...it is .. i think.. impossible for you to take a negative number with 3 consecutive even integers and add them up to 24.
and 30 doesnt work
Nope it was 30
I just got the answers
30+32+34 is 96?
30 + 32 + 34 \(\large \ne 84\) so the answer cannot be 30.... the answer to your question is 26... 26 + 28 + 30 = 84 looks like the correct choice is not there or the problem was mistyped... this is your orginal question: 3. The sum of three consecutive even integers is 84. What is the least of these numbers? (Points : 1) -34 -30 -26 30