A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Because the density of a dilute aqueous solution is close to 1.00 g/mL, we
frequently equate 1 g of water with 1 mL of water, although this equivalence is only
approximate. Therefore, 1 ppm corresponds to 1 µg/mL ( 1 mg/L) and 1 ppb is 1 ng/mL
( 1 g/L).
I do not understand where they are getting those micrometer and nanometer measurements..
anonymous
 3 years ago
Because the density of a dilute aqueous solution is close to 1.00 g/mL, we frequently equate 1 g of water with 1 mL of water, although this equivalence is only approximate. Therefore, 1 ppm corresponds to 1 µg/mL ( 1 mg/L) and 1 ppb is 1 ng/mL ( 1 g/L). I do not understand where they are getting those micrometer and nanometer measurements..

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think ppm and ppb is indicate how it's concentrate but not affect itself density of matter, ppm can indicate any substance such as have 1g of NaCl in 10^6 ml solution, the density of NaCl still constant

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0remind that ppm ppb molar or molal is concentration or molar density but density is mass density (ppm or ppb can be report as mass density as well) things that make you confuse, may be cause of its unit is similar >> mass/volume

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01 ppm = \(10^{6}\) = \(\Large \frac {10^{6}g}{1g}\)=\(\Large \frac {1\mu g}{1g}\), which corresponds in water to: \(\Large \frac {1\mu g}{1mL}\) = \(\Large \frac {1mg}{1L}\)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.