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Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[\sum_{k=1}^{49}(k+1)^3k^3\] evaluate
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
no formular jus a series
 one year ago

J_Liu Group TitleBest ResponseYou've already chosen the best response.0
That series is just saying when you plug in k = 1, 2, 3, 4....49 and add them up, there should be a formula for the series to make the calculation easier. It is possible to calculate every term.
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[2^31^3+3^32^3+4^33^3+...+50^349^3\]
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
it appears to be a telescoping series
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
does it mean numbers are cancelling out
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
i think the anwers is \[1^3+50^3\]
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[\sum_{k=1}^{49}(k+1)^3k^3\] \[\sum_{k=1}^{49}(k+1)^3\sum_{k=1}^{49}k^3\] \[\sum_{k=1+1}^{49+1}(k)^3\sum_{k=1}^{49}k^3\] \[\sum_{k=2}^{50}k^3\sum_{k=1}^{49}k^3=50^31^3\]
 one year ago
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