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JonaskBest ResponseYou've already chosen the best response.0
\[\sum_{k=1}^{49}(k+1)^3k^3\] evaluate
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
no formular jus a series
 one year ago

J_LiuBest ResponseYou've already chosen the best response.0
That series is just saying when you plug in k = 1, 2, 3, 4....49 and add them up, there should be a formula for the series to make the calculation easier. It is possible to calculate every term.
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
\[2^31^3+3^32^3+4^33^3+...+50^349^3\]
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
it appears to be a telescoping series
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
does it mean numbers are cancelling out
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
i think the anwers is \[1^3+50^3\]
 one year ago

amistre64Best ResponseYou've already chosen the best response.1
\[\sum_{k=1}^{49}(k+1)^3k^3\] \[\sum_{k=1}^{49}(k+1)^3\sum_{k=1}^{49}k^3\] \[\sum_{k=1+1}^{49+1}(k)^3\sum_{k=1}^{49}k^3\] \[\sum_{k=2}^{50}k^3\sum_{k=1}^{49}k^3=50^31^3\]
 one year ago
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