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Jonask
 3 years ago
sigma
Jonask
 3 years ago
sigma

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Jonask
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{k=1}^{49}(k+1)^3k^3\] evaluate

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.0no formular jus a series

J_Liu
 3 years ago
Best ResponseYou've already chosen the best response.0That series is just saying when you plug in k = 1, 2, 3, 4....49 and add them up, there should be a formula for the series to make the calculation easier. It is possible to calculate every term.

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.0\[2^31^3+3^32^3+4^33^3+...+50^349^3\]

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0it appears to be a telescoping series

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.0does it mean numbers are cancelling out

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.0i think the anwers is \[1^3+50^3\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[\sum_{k=1}^{49}(k+1)^3k^3\] \[\sum_{k=1}^{49}(k+1)^3\sum_{k=1}^{49}k^3\] \[\sum_{k=1+1}^{49+1}(k)^3\sum_{k=1}^{49}k^3\] \[\sum_{k=2}^{50}k^3\sum_{k=1}^{49}k^3=50^31^3\]
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