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Tati_Lee

  • 3 years ago

simplify

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  1. Tati_Lee
    • 3 years ago
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    \[\frac{ 4x }{ 9 }+\frac{ x-10 }{ 9 }\]

  2. TheMind
    • 3 years ago
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    so easy tati

  3. TheMind
    • 3 years ago
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    LCM=9

  4. hartnn
    • 3 years ago
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    common denominator so \(\huge \frac{4x+x-10}{9}\)

  5. hartnn
    • 3 years ago
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    whats 4x+x ?

  6. Tati_Lee
    • 3 years ago
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    thank i got it

  7. Tati_Lee
    • 3 years ago
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    \[\frac{ 5x-10 }{ 9 }\] ?

  8. Tati_Lee
    • 3 years ago
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    @hartnn

  9. hartnn
    • 3 years ago
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    yup, thats correct :)

  10. Tati_Lee
    • 3 years ago
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    thank you can you help me with like 5 more ?

  11. hartnn
    • 3 years ago
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    only 5 ?

  12. Tati_Lee
    • 3 years ago
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    yes

  13. hartnn
    • 3 years ago
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    whats next ?

  14. Tati_Lee
    • 3 years ago
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    \[\frac{ t^{2}+6 }{ t-1 }-\frac{ 7 }{ t-1 }\]

  15. hartnn
    • 3 years ago
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    again common denominator, \(\frac{t^2+6-7}{t-1}\)

  16. Tati_Lee
    • 3 years ago
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    sorry the 6 has a t next to it

  17. hartnn
    • 3 years ago
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    whats 6-7 ?

  18. hartnn
    • 3 years ago
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    so can u factor t^2+6t-7 ?

  19. Tati_Lee
    • 3 years ago
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    umm yes ?

  20. hartnn
    • 3 years ago
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    then tell me the two factors....

  21. Tati_Lee
    • 3 years ago
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    ik you can factors that .. wouldnt one of the numbers be negative

  22. hartnn
    • 3 years ago
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    tell me 2 numbers whose sum is 6 and product is -7 yes,one of them is negative.

  23. Tati_Lee
    • 3 years ago
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    (t-6)(t+1) ??

  24. hartnn
    • 3 years ago
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    nice, its (t+7)(t-1) then cancel out t-1 from numerator and denominator what do u get finally ?

  25. Tati_Lee
    • 3 years ago
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    (t+7)

  26. hartnn
    • 3 years ago
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    thats it. :)

  27. Tati_Lee
    • 3 years ago
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    okay the next one \[\frac{ 3 }{ x }+\frac{ 13 }{ x-11 }\]

  28. Tati_Lee
    • 3 years ago
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    wouldnt the top be 16

  29. hartnn
    • 3 years ago
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    nopes,its not the same denominator now.

  30. hartnn
    • 3 years ago
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    u need to cross multiply..... can u ?

  31. Tati_Lee
    • 3 years ago
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    3x-33+13x

  32. hartnn
    • 3 years ago
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    yup,thats the correct numerator.... which will be 16x-33 and what will be denominator?

  33. Tati_Lee
    • 3 years ago
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    uhhh i dont know i thought the denominator would cancel out cross we crossed multiplied

  34. hartnn
    • 3 years ago
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    nopes it would be \(\huge \frac{16x-33}{x(x-11)}\)

  35. Tati_Lee
    • 3 years ago
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    ohh okay ... \[\frac{ 5 }{ 4x ^{2}y }-\frac{ y }{ 14xy }\]

  36. Tati_Lee
    • 3 years ago
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    ??

  37. hartnn
    • 3 years ago
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    sorry, i kinda lost connection :( tell me the LCM of 4x^y and 14xy ?

  38. Tati_Lee
    • 3 years ago
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    oh okay it would be 2xy

  39. hartnn
    • 3 years ago
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    right, so can u solve that further ?

  40. Tati_Lee
    • 3 years ago
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    what do you mean?

  41. hartnn
    • 3 years ago
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    ok, i'll write next step, see it that makes sense \(\huge \frac{5(7)}{28x^2y}-\frac{y(2x)}{28x^2y}\)

  42. Tati_Lee
    • 3 years ago
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    ohh okay .. \[\frac{ 35 }{28x ^{2}y }-\frac{ 2xy }{ 28x ^{2} y}\]

  43. Tati_Lee
    • 3 years ago
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    then combine the denominator

  44. hartnn
    • 3 years ago
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    but did u get how i got that ? yes,then combine denom.

  45. Tati_Lee
    • 3 years ago
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    yea i saw you got that,

  46. hartnn
    • 3 years ago
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    so finally u get (35- 2xy)/(28x^2y) ok?

  47. Tati_Lee
    • 3 years ago
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    \[\frac{ x ^{2}+2x }{12x+54 }-\frac{ 3x }{ 8x+36 }\]

  48. Tati_Lee
    • 3 years ago
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    would i combine the like terms on the bottom & top

  49. hartnn
    • 3 years ago
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    nopes, first can u write 12x+54 as 6(2x+9) ??

  50. Tati_Lee
    • 3 years ago
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    you can cause that would equal the original equation

  51. hartnn
    • 3 years ago
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    so how would u write 8x+36 ?

  52. Tati_Lee
    • 3 years ago
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    8 doesn't go into 36 tho

  53. Tati_Lee
    • 3 years ago
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    36 doesnt go into 8 i mean

  54. hartnn
    • 3 years ago
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    what about 4 ? 36 and 8 both go into 4.

  55. Tati_Lee
    • 3 years ago
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    4(2x+9)

  56. hartnn
    • 3 years ago
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    right so u have \(\huge\frac{ x ^{2}+2x }{12x+54 }-\frac{ 3x }{ 8x+36 }=\frac{ x ^{2}+2x }{6(2x+9) }-\frac{ 3x }{ 4(2x+9) }\) can u figure out next step ?

  57. Tati_Lee
    • 3 years ago
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    you would factor the top

  58. hartnn
    • 3 years ago
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    before that... \(\huge\frac{ x ^{2}+2x }{6(2x+9) }-\frac{ 3x }{ 4(2x+9) }=\frac{2( x ^{2}+2x) }{12(2x+9) }-\frac{ 4(3x) }{ 12(2x+9) }\) u see how i tried to make the denominator same ?

  59. hartnn
    • 3 years ago
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    sorry it would be 3 in the numerator of 2nd fraction 3(3x)

  60. Tati_Lee
    • 3 years ago
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    i see it i see it it makes sense so then you would take away the denominator?

  61. hartnn
    • 3 years ago
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    take away ? since the denominator is common u combine the numerators. (2x^2+4x-9x)\(12(2x-9))

  62. Tati_Lee
    • 3 years ago
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    yea thats what i meant

  63. Tati_Lee
    • 3 years ago
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    would the answer be 2x^2-5x/(12(2x-9)

  64. hartnn
    • 3 years ago
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    yup, thats correct. (2x^2-5x)/(12(2x-9))

  65. Tati_Lee
    • 3 years ago
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    awesome .. there is one more

  66. hartnn
    • 3 years ago
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    ok, ask.

  67. Tati_Lee
    • 3 years ago
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    \[\frac{ 2 }{ x ^{2}8x+15 } +\frac{ 1 }{ x ^{2} +11x+30}\]

  68. Tati_Lee
    • 3 years ago
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    x^2 + 8 **

  69. hartnn
    • 3 years ago
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    can u factor both the quadratic polynomials in denom. ?

  70. Tati_Lee
    • 3 years ago
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    i dont think so, im not sure

  71. hartnn
    • 3 years ago
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    x^2+8x+15 = (x+5)(x+3) and x^2+11x+30=(x+5)(x+6) ok?

  72. Tati_Lee
    • 3 years ago
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    ohhhhhh okay

  73. Tati_Lee
    • 3 years ago
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    \[\frac{ 3 }{ (x+3)(x+6) } or \frac{ 2 }{ (x+3) }+\frac{ 1 }{ (x+6)}\]

  74. hartnn
    • 3 years ago
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    \(\large\frac{ 2 }{(x+5)(x+3)} +\frac{ 1 }{(x+5)(x+6)}=\frac{ 2(x+6) }{(x+6)(x+5)(x+3)} +\frac{ (x+3) }{(x+3)(x+5)(x+6)}\) the idea is to make the denominator same, so that u can combine numerator....

  75. Tati_Lee
    • 3 years ago
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    oh okay

  76. hartnn
    • 3 years ago
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    so after combining numerators , u get 2x+12+x+3 = ?

  77. Tati_Lee
    • 3 years ago
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    3x+15

  78. hartnn
    • 3 years ago
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    can u take out something common from that?

  79. Tati_Lee
    • 3 years ago
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    5

  80. hartnn
    • 3 years ago
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    i would say 3 3(x+5)

  81. Tati_Lee
    • 3 years ago
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    so thats the answer?

  82. hartnn
    • 3 years ago
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    the numerator's (x+5) cancels with denominator's (x+5) to give u \(\huge \frac{3}{(x+3)(x+6)}\)

  83. Tati_Lee
    • 3 years ago
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    thank you soo much, you're amazing!

  84. hartnn
    • 3 years ago
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    welcome :) u too are awesome ;)

  85. Tati_Lee
    • 3 years ago
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    thanks ^_^

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