Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

\[\frac{ 4x }{ 9 }+\frac{ x-10 }{ 9 }\]
so easy tati
LCM=9

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

common denominator so \(\huge \frac{4x+x-10}{9}\)
whats 4x+x ?
thank i got it
\[\frac{ 5x-10 }{ 9 }\] ?
yup, thats correct :)
thank you can you help me with like 5 more ?
only 5 ?
yes
whats next ?
\[\frac{ t^{2}+6 }{ t-1 }-\frac{ 7 }{ t-1 }\]
again common denominator, \(\frac{t^2+6-7}{t-1}\)
sorry the 6 has a t next to it
whats 6-7 ?
so can u factor t^2+6t-7 ?
umm yes ?
then tell me the two factors....
ik you can factors that .. wouldnt one of the numbers be negative
tell me 2 numbers whose sum is 6 and product is -7 yes,one of them is negative.
(t-6)(t+1) ??
nice, its (t+7)(t-1) then cancel out t-1 from numerator and denominator what do u get finally ?
(t+7)
thats it. :)
okay the next one \[\frac{ 3 }{ x }+\frac{ 13 }{ x-11 }\]
wouldnt the top be 16
nopes,its not the same denominator now.
u need to cross multiply..... can u ?
3x-33+13x
yup,thats the correct numerator.... which will be 16x-33 and what will be denominator?
uhhh i dont know i thought the denominator would cancel out cross we crossed multiplied
nopes it would be \(\huge \frac{16x-33}{x(x-11)}\)
ohh okay ... \[\frac{ 5 }{ 4x ^{2}y }-\frac{ y }{ 14xy }\]
??
sorry, i kinda lost connection :( tell me the LCM of 4x^y and 14xy ?
oh okay it would be 2xy
right, so can u solve that further ?
what do you mean?
ok, i'll write next step, see it that makes sense \(\huge \frac{5(7)}{28x^2y}-\frac{y(2x)}{28x^2y}\)
ohh okay .. \[\frac{ 35 }{28x ^{2}y }-\frac{ 2xy }{ 28x ^{2} y}\]
then combine the denominator
but did u get how i got that ? yes,then combine denom.
yea i saw you got that,
so finally u get (35- 2xy)/(28x^2y) ok?
\[\frac{ x ^{2}+2x }{12x+54 }-\frac{ 3x }{ 8x+36 }\]
would i combine the like terms on the bottom & top
nopes, first can u write 12x+54 as 6(2x+9) ??
you can cause that would equal the original equation
so how would u write 8x+36 ?
8 doesn't go into 36 tho
36 doesnt go into 8 i mean
what about 4 ? 36 and 8 both go into 4.
4(2x+9)
right so u have \(\huge\frac{ x ^{2}+2x }{12x+54 }-\frac{ 3x }{ 8x+36 }=\frac{ x ^{2}+2x }{6(2x+9) }-\frac{ 3x }{ 4(2x+9) }\) can u figure out next step ?
you would factor the top
before that... \(\huge\frac{ x ^{2}+2x }{6(2x+9) }-\frac{ 3x }{ 4(2x+9) }=\frac{2( x ^{2}+2x) }{12(2x+9) }-\frac{ 4(3x) }{ 12(2x+9) }\) u see how i tried to make the denominator same ?
sorry it would be 3 in the numerator of 2nd fraction 3(3x)
i see it i see it it makes sense so then you would take away the denominator?
take away ? since the denominator is common u combine the numerators. (2x^2+4x-9x)\(12(2x-9))
yea thats what i meant
would the answer be 2x^2-5x/(12(2x-9)
yup, thats correct. (2x^2-5x)/(12(2x-9))
awesome .. there is one more
ok, ask.
\[\frac{ 2 }{ x ^{2}8x+15 } +\frac{ 1 }{ x ^{2} +11x+30}\]
x^2 + 8 **
can u factor both the quadratic polynomials in denom. ?
i dont think so, im not sure
x^2+8x+15 = (x+5)(x+3) and x^2+11x+30=(x+5)(x+6) ok?
ohhhhhh okay
\[\frac{ 3 }{ (x+3)(x+6) } or \frac{ 2 }{ (x+3) }+\frac{ 1 }{ (x+6)}\]
\(\large\frac{ 2 }{(x+5)(x+3)} +\frac{ 1 }{(x+5)(x+6)}=\frac{ 2(x+6) }{(x+6)(x+5)(x+3)} +\frac{ (x+3) }{(x+3)(x+5)(x+6)}\) the idea is to make the denominator same, so that u can combine numerator....
oh okay
so after combining numerators , u get 2x+12+x+3 = ?
3x+15
can u take out something common from that?
5
i would say 3 3(x+5)
so thats the answer?
the numerator's (x+5) cancels with denominator's (x+5) to give u \(\huge \frac{3}{(x+3)(x+6)}\)
thank you soo much, you're amazing!
welcome :) u too are awesome ;)
thanks ^_^

Not the answer you are looking for?

Search for more explanations.

Ask your own question