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Do they look vertically opposite to you?
Yes, so that's probably false. Maybe the angles are a linear pair?
Look up the definition of vertical angles. http://www.mathsisfun.com/geometry/vertical-angles.html
\[\angle LSM = 145 + 35\]
Degrees, that is. \[\angle OSN = 90\]
there is no way to know the actual degrees in this diagram with no given angle information. However, we can state if the angles are vertical or not.
So, the angles are a linear pair? Both supplementary and adjacent.
I'm using a protractor.
LSM and OSN are vertical angles, they are equal.
But vertical angles are congruent. Horizontally, LSO and MNS are congruent, but not vertically.
The vertical is just a term, it doesn't actually mean it has to be vertical it simply means/...|dw:1347485797597:dw|
angle a = angle b & angle d = angle c
It's still odd how each angle equals 180 and 90 degrees. Why wouldn't they be a linear pair? If I center the protractor on S, then each angle can be identified as 145 + 35 and 90 degrees.
the adjacent angles are supplemental so i understand where you are getting the 180 but am unsure of where your 90 degrees is coming from...
It doesn't matter if the angle is smaller? The top and the bottom just don't seem that equal to each-other.
by top and bottom do you mean...|dw:1347486791023:dw|
Top angle would be
i think that the fact that the quadrilateral is irregular is throwing you off about the angles. With your protractor you should be able to prove that
I think so. Wow, what a problem. Thank you very much. :)