anonymous
  • anonymous
Is \((AB)^{-1}=A^{-1}B^{-1}\) for square matrices A and B?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
TuringTest
  • TuringTest
yes
anonymous
  • anonymous
really? I couldn't find anything that says so. Wikipedia or google...
jim_thompson5910
  • jim_thompson5910
Shouldn't it be \(\Large (AB)^{-1}=B^{-1}A^{-1}\) ???

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Yeah that's what I thought too.
anonymous
  • anonymous
I guess the matrices I tried it out on were trivial...
jim_thompson5910
  • jim_thompson5910
AB = C (AB)^(-1)(AB) = (AB)^(-1)C I = (AB)^(-1)AB I = B^(-1)A^(-1)AB I = B^(-1)[A^(-1)A]B I = B^(-1)[I]B I = B^(-1)B I = I It's explained better here http://mathworld.wolfram.com/MatrixInverse.html
TuringTest
  • TuringTest
Oh I totally didn't even read it... sorry :/

Looking for something else?

Not the answer you are looking for? Search for more explanations.