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vf321Best ResponseYou've already chosen the best response.0
really? I couldn't find anything that says so. Wikipedia or google...
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.2
Shouldn't it be \(\Large (AB)^{1}=B^{1}A^{1}\) ???
 one year ago

vf321Best ResponseYou've already chosen the best response.0
Yeah that's what I thought too.
 one year ago

vf321Best ResponseYou've already chosen the best response.0
I guess the matrices I tried it out on were trivial...
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.2
AB = C (AB)^(1)(AB) = (AB)^(1)C I = (AB)^(1)AB I = B^(1)A^(1)AB I = B^(1)[A^(1)A]B I = B^(1)[I]B I = B^(1)B I = I It's explained better here http://mathworld.wolfram.com/MatrixInverse.html
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
Oh I totally didn't even read it... sorry :/
 one year ago
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