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vivalakoda

  • 3 years ago

What is the equation in standard form of the line which passes through (6, 3) and has a slope of ? 2x + 3y = 3 2x – 3y = 3 3x + 2y = 3 3x – 2y = 3

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  1. Nameless
    • 3 years ago
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    do you know what the standard form of a linear equation looks like?

  2. vivalakoda
    • 3 years ago
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    No

  3. Nameless
    • 3 years ago
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    y=mx+b m is the slope and b is the y intercept. so.. is your question incomplete or are u supposed to use the given equations to compute the slope?

  4. vivalakoda
    • 3 years ago
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    the slope is 2/3

  5. jim_thompson5910
    • 3 years ago
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    Hint: In Ax + By = C the slope is -A/B In Ax - By = C the slope is A/B

  6. Nameless
    • 3 years ago
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    if you know the slope and the point it passes through you can use the point slope formula to figure out the equation of the line. y-y1 = m(x-x1)

  7. Nameless
    • 3 years ago
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    so y - 3 = 2/3(x - 6)

  8. Nameless
    • 3 years ago
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    can you solve from there and rearrange to the right form?

  9. vivalakoda
    • 3 years ago
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    I can't get the fraction part figured out

  10. jim_thompson5910
    • 3 years ago
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    Hint: start with y - 3 = 2/3(x - 6) and multiply everything (but the stuff in the parenthesis) by 3 to get 3y - 9 = 2(x-6)

  11. vivalakoda
    • 3 years ago
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    I got 2x-3y=3.

  12. jim_thompson5910
    • 3 years ago
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    you are correct

  13. vivalakoda
    • 3 years ago
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    Awesome. Thanks muchos

  14. jim_thompson5910
    • 3 years ago
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    yw

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