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AcidRa1n Group Title

Determine whether y varies directly with x. If so find the constant variation. y = 12x ****** The answer is Yes; 12 I dont understand how this is the answer. Can someone help me?

  • 2 years ago
  • 2 years ago

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  1. Nameless Group Title
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    my guess would be that its because y is equal to whatever 12(x) is going to be.

    • 2 years ago
  2. Nameless Group Title
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    but that seems too easy

    • 2 years ago
  3. AcidRa1n Group Title
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    i know. How about y = 4x+1

    • 2 years ago
  4. AcidRa1n Group Title
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    the asnwer is no

    • 2 years ago
  5. Nameless Group Title
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    i am probably in over my head.. sorry

    • 2 years ago
  6. lgbasallote Group Title
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    here's something you can remember... if y and x are in one line...then it's a direct variation if either y or x is in the denominator...then inverse variation

    • 2 years ago
  7. lgbasallote Group Title
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    \[y = kx \leftarrow \; \text{direct variation}\] \[y = \frac kx \leftarrow \; \text{inverse variation}\]

    • 2 years ago
  8. AcidRa1n Group Title
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    ok so how does that apply to my first problem

    • 2 years ago
  9. lgbasallote Group Title
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    y = 12x <--in the for y = kx <--can you see that?

    • 2 years ago
  10. lgbasallote Group Title
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    in the form*

    • 2 years ago
  11. AcidRa1n Group Title
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    oh ok so how does it arie directly with x.. Im sorry im just not seeing the picture

    • 2 years ago
  12. AcidRa1n Group Title
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    varie* My teacher isnt that good

    • 2 years ago
  13. lgbasallote Group Title
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    look at what i said above about y = kx

    • 2 years ago
  14. AcidRa1n Group Title
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    yeah I know but what does K mean how the flutter does it varie with anything?

    • 2 years ago
  15. lgbasallote Group Title
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    k is a constant

    • 2 years ago
  16. lgbasallote Group Title
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    it is called the proportionality constant

    • 2 years ago
  17. lgbasallote Group Title
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    it means its value doesnt matter because it is constant..in other words...always stays the same

    • 2 years ago
  18. AcidRa1n Group Title
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    ok now I get why 12 is there.. So now explain the rest please?

    • 2 years ago
  19. lgbasallote Group Title
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    in your terms... k is the constant variation

    • 2 years ago
  20. lgbasallote Group Title
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    first tell me... do you agree that y = 12x is in the form y = kx?

    • 2 years ago
  21. AcidRa1n Group Title
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    is y = k? which is 12? and how does that varie to x?

    • 2 years ago
  22. AcidRa1n Group Title
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    Yeah I get that

    • 2 years ago
  23. lgbasallote Group Title
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    what do you see as difference between \[\huge y = kx\] and \[\huge y = 12x\]

    • 2 years ago
  24. AcidRa1n Group Title
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    yeah I see that

    • 2 years ago
  25. lgbasallote Group Title
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    spot the difference

    • 2 years ago
  26. lgbasallote Group Title
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    not the similarity

    • 2 years ago
  27. AcidRa1n Group Title
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    yeah

    • 2 years ago
  28. lgbasallote Group Title
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    what do you mean yeah?

    • 2 years ago
  29. AcidRa1n Group Title
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    I spot the difference

    • 2 years ago
  30. lgbasallote Group Title
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    what's the difference??

    • 2 years ago
  31. AcidRa1n Group Title
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    12 instead of K

    • 2 years ago
  32. lgbasallote Group Title
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    RIGHT! that's why 12 is the constant variation

    • 2 years ago
  33. lgbasallote Group Title
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    because k is the constant variation..and k = 12

    • 2 years ago
  34. AcidRa1n Group Title
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    ohhh K= Constant Variationnnnnn

    • 2 years ago
  35. lgbasallote Group Title
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    yes!

    • 2 years ago
  36. AcidRa1n Group Title
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    lmfao face to palm**

    • 2 years ago
  37. AcidRa1n Group Title
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    ok so what about this one y = 4x + 1

    • 2 years ago
  38. lgbasallote Group Title
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    the answer to that one was "NOT direct variation" right?

    • 2 years ago
  39. AcidRa1n Group Title
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    yes

    • 2 years ago
  40. lgbasallote Group Title
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    that's because of the 1 y = 4x + 1 is not in the form y = kx because of that 1

    • 2 years ago
  41. AcidRa1n Group Title
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    what about y - 6x = 0

    • 2 years ago
  42. AcidRa1n Group Title
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    ;)

    • 2 years ago
  43. lgbasallote Group Title
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    simplify it first

    • 2 years ago
  44. lgbasallote Group Title
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    solve for y first

    • 2 years ago
  45. AcidRa1n Group Title
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    can you do it?

    • 2 years ago
  46. AcidRa1n Group Title
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    I dont wnana get confused

    • 2 years ago
  47. lgbasallote Group Title
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    add 6x to both sides

    • 2 years ago
  48. AcidRa1n Group Title
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    add 6 to 0?

    • 2 years ago
  49. lgbasallote Group Title
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    6x..not 6

    • 2 years ago
  50. AcidRa1n Group Title
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    yeah

    • 2 years ago
  51. AcidRa1n Group Title
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    y-=6x?

    • 2 years ago
  52. AcidRa1n Group Title
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    im a idiot

    • 2 years ago
  53. lgbasallote Group Title
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    y-?

    • 2 years ago
  54. AcidRa1n Group Title
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    lmfao it was negative

    • 2 years ago
  55. AcidRa1n Group Title
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    OH NVM

    • 2 years ago
  56. AcidRa1n Group Title
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    alright so the answer is 6!

    • 2 years ago
  57. lgbasallote Group Title
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    yes

    • 2 years ago
  58. AcidRa1n Group Title
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    what about y _ 3 = -3x

    • 2 years ago
  59. AcidRa1n Group Title
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    -

    • 2 years ago
  60. lgbasallote Group Title
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    what do you think?

    • 2 years ago
  61. AcidRa1n Group Title
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    add 3 to both sides

    • 2 years ago
  62. AcidRa1n Group Title
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    y= x?

    • 2 years ago
  63. lgbasallote Group Title
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    you can't combine 3 and 3x

    • 2 years ago
  64. AcidRa1n Group Title
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    is that a constant variation?

    • 2 years ago
  65. lgbasallote Group Title
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    no..im just talking about algebra

    • 2 years ago
  66. AcidRa1n Group Title
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    Ah forget about that one can you help me with proportions? i'll open up a new question

    • 2 years ago
  67. lgbasallote Group Title
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    i have to go soon

    • 2 years ago
  68. AcidRa1n Group Title
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    awe ur like the best lol

    • 2 years ago
  69. lgbasallote Group Title
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    call saifoo or amistre

    • 2 years ago
  70. AcidRa1n Group Title
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    eh Saifoo is a fool now he used to be cool

    • 2 years ago
  71. AcidRa1n Group Title
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    amistre doesnt help me anymore

    • 2 years ago
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