AcidRa1n
Determine whether y varies directly with x. If so find the constant variation.
y = 12x ****** The answer is Yes; 12
I dont understand how this is the answer. Can someone help me?
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Nameless
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my guess would be that its because y is equal to whatever 12(x) is going to be.
Nameless
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but that seems too easy
AcidRa1n
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i know. How about y = 4x+1
AcidRa1n
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the asnwer is no
Nameless
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i am probably in over my head.. sorry
lgbasallote
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here's something you can remember...
if y and x are in one line...then it's a direct variation
if either y or x is in the denominator...then inverse variation
lgbasallote
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\[y = kx \leftarrow \; \text{direct variation}\]
\[y = \frac kx \leftarrow \; \text{inverse variation}\]
AcidRa1n
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ok so how does that apply to my first problem
lgbasallote
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y = 12x <in the for y = kx <can you see that?
lgbasallote
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in the form*
AcidRa1n
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oh ok so how does it arie directly with x.. Im sorry im just not seeing the picture
AcidRa1n
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varie* My teacher isnt that good
lgbasallote
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look at what i said above about y = kx
AcidRa1n
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yeah I know but what does K mean how the flutter does it varie with anything?
lgbasallote
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k is a constant
lgbasallote
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it is called the proportionality constant
lgbasallote
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it means its value doesnt matter because it is constant..in other words...always stays the same
AcidRa1n
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ok now I get why 12 is there.. So now explain the rest please?
lgbasallote
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in your terms... k is the constant variation
lgbasallote
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first tell me... do you agree that y = 12x is in the form y = kx?
AcidRa1n
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is y = k? which is 12? and how does that varie to x?
AcidRa1n
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Yeah I get that
lgbasallote
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what do you see as difference between \[\huge y = kx\]
and \[\huge y = 12x\]
AcidRa1n
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yeah I see that
lgbasallote
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spot the difference
lgbasallote
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not the similarity
AcidRa1n
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yeah
lgbasallote
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what do you mean yeah?
AcidRa1n
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I spot the difference
lgbasallote
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what's the difference??
AcidRa1n
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12 instead of K
lgbasallote
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RIGHT! that's why 12 is the constant variation
lgbasallote
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because k is the constant variation..and k = 12
AcidRa1n
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ohhh K= Constant Variationnnnnn
lgbasallote
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yes!
AcidRa1n
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lmfao face to palm**
AcidRa1n
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ok so what about this one y = 4x + 1
lgbasallote
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the answer to that one was "NOT direct variation" right?
AcidRa1n
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yes
lgbasallote
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that's because of the 1
y = 4x + 1 is not in the form y = kx because of that 1
AcidRa1n
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what about y  6x = 0
AcidRa1n
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;)
lgbasallote
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simplify it first
lgbasallote
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solve for y first
AcidRa1n
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can you do it?
AcidRa1n
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I dont wnana get confused
lgbasallote
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add 6x to both sides
AcidRa1n
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add 6 to 0?
lgbasallote
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6x..not 6
AcidRa1n
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yeah
AcidRa1n
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y=6x?
AcidRa1n
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im a idiot
lgbasallote
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y?
AcidRa1n
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lmfao it was negative
AcidRa1n
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OH NVM
AcidRa1n
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alright so the answer is 6!
lgbasallote
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yes
AcidRa1n
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what about y _ 3 = 3x
AcidRa1n
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lgbasallote
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what do you think?
AcidRa1n
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add 3 to both sides
AcidRa1n
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y= x?
lgbasallote
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you can't combine 3 and 3x
AcidRa1n
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is that a constant variation?
lgbasallote
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no..im just talking about algebra
AcidRa1n
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Ah forget about that one can you help me with proportions? i'll open up a new question
lgbasallote
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i have to go soon
AcidRa1n
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awe ur like the best lol
lgbasallote
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call saifoo or amistre
AcidRa1n
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eh Saifoo is a fool now he used to be cool
AcidRa1n
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amistre doesnt help me anymore