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zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
is there any reason you just cant plug in 3?
 one year ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.0
^^ ya substitute 3 for x
 one year ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
i dont think. there's any steps i would have to show?
 one year ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
dw:1347497171437:dw
 one year ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
do you mean this?
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
note: unless ding so makes you devide by zero, take a sqrt( a negative number ), or take a ln( negative number ), then you can plug in for x
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
you can show what ever step you would in algebra.
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
(31)^2 * (3+1) = 2^2 * 4 .....
 one year ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow 2}(x1)^2(x+1)\]
 one year ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
sorry not 2 but 3
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
3 or 2? Not that it makes a dif here, just plug in for x
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
now if it where lim x>3 of 1/(3x) then you could not just plug in for x because you would get 1/0
 one year ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
find the indicated onesided limit. if the limiting value is inifinte indicate whther is is \[+\infty or \], \[\lim_{x \rightarrow 4} (3x9)\]
 one year ago
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