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zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
is there any reason you just cant plug in 3?
 2 years ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.0
^^ ya substitute 3 for x
 2 years ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
i dont think. there's any steps i would have to show?
 2 years ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
dw:1347497171437:dw
 2 years ago

LeeYeongKyu Group TitleBest ResponseYou've already chosen the best response.0
do you mean this?
 2 years ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
note: unless ding so makes you devide by zero, take a sqrt( a negative number ), or take a ln( negative number ), then you can plug in for x
 2 years ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
you can show what ever step you would in algebra.
 2 years ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
(31)^2 * (3+1) = 2^2 * 4 .....
 2 years ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow 2}(x1)^2(x+1)\]
 2 years ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
sorry not 2 but 3
 2 years ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
3 or 2? Not that it makes a dif here, just plug in for x
 2 years ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
now if it where lim x>3 of 1/(3x) then you could not just plug in for x because you would get 1/0
 2 years ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
find the indicated onesided limit. if the limiting value is inifinte indicate whther is is \[+\infty or \], \[\lim_{x \rightarrow 4} (3x9)\]
 2 years ago
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