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Simply posting your actual question would be great

im going to take a pic :3

the limit is x->-1/2+

You've got like 5 questions circled. Which one is it?

#38

perhaps factorising the numerator and denominator will allow you to cancel a common factor

kk

limit as x goes to ???

-1/2

there is a common factor that is evident when you factorise numerator and denominator

i wouldn't do that, i would plug in first

If you plug in first, you're definitely going to get a denominator you won't like

so plugin -1/2 im kinda confused

Why waste your time trying to evaluate before factoring? Seems silly

kk

This limit is begging for L'Hopital's Rule.....

it doesn't need L'Hopital ... just factor to find it.... don't over think it

im kinda confuzzled a bit :3

i can do lhopital in my head on this... but i guess it depends

That's because there's too many people trying to give their version of how to solve it.

looking at the type of questions you need to factorise to find the limit..

abanna, just listen to satellite, he's always right lol

I object to that statement^

if you get \(\frac{a}{0}\) where \(a\) is some non zero number, then there is no limit

and if you get \(\frac{0}{0}\) then you know to factor and cancel AND you know how to factor

I see what you're saying now, @satellite. I usually do that part in my head first, but not on paper.

oh ok

@abannavong what level of maths is this...

and your job is then only to find the other factor, as @campbell_st wrote above

AB calculus, aka cal 1

AP Calc :3

ok... so still high school... just I'm in australia...

yeah in grade 12

thanks... I think you get 5/8 as the limit... good luck

thank you @campbell_st