## swissgirl 3 years ago Hey is anyone familiar with 4 digit chopping arithmetic?

1. CliffSedge

Doesn't sound familiar, but I might know what you mean by another name.

2. swissgirl

Like at what point do I chop?

3. swissgirl

Like you only have four digits after the decimal

4. swissgirl

Do I chop at the end or at every point that there is more than 4 digits after the decimal?

5. CliffSedge

Do you mean rounding, truncating, or determining significant figures?

6. swissgirl

def not rounding

7. swissgirl

idk what the others r

8. CliffSedge

Sounds like you mean truncating then. Truncate = chop off.

9. swissgirl

ohhhh lol Ya like when do i chop off?

10. CliffSedge

If you want your answer to only have 4 digits, then count four digits starting from the left, keep those four and get rid of all the rest.

11. CliffSedge

Example. 123.456789 truncated to four digits = 123.4 If you want to truncate to a particular place value, say, the ten-thousandths place, then 123.4567 is truncated at the fourth digit after the decimal point.

12. swissgirl

yes but my question is as follows like do u chop off like at any point while u r solving or only once u have solved the whole equation?

13. swissgirl

Like do u contiously chop off?

14. CliffSedge

Ah, only round or truncate at the very end of your calculations! That is very important.

15. Agent47

no, only after u finish solving

16. swissgirl

THANNNKKKSSSS lol

17. CliffSedge

That is a matter of significant figures then. If you round or truncate in the middle of your calculations you'll get round-off error and all sorts of other nasty business.

18. swissgirl

ya i figured so i just had to dbl check

19. CliffSedge

Check this example: 12.34567 times 2.98765 = 36.88454098... Truncated at the fourth digit is 36.88 But if you 'chop' first then, 12.34 times 2.987 = 36.85958, which would be chopped to 36.85. That is off from the correct answer by 3/100.

20. swissgirl

Thanks