Study23 2 years ago Logarithm help - see drawing...

1. Study23

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2. Study23

How do I solve that?

3. Study23

Is it like 1/3 or something? Because 2^3 = 8...

4. satellite73

ask yourself what power you would raise the number 8 to in order to get 2 i.e. solve $$8^x=2$$ for $$x$$

5. satellite73

yes, it is $$\frac{1}{3}$$ because $8^{\frac{1}{3}}=\sqrt[3]{8}=2$

6. hartnn

use the property of logarithm: $$\huge log_ba=\frac{log a}{log b}$$ yup its 1/3.

7. Study23

Thanks @hartnn & @satellite73!

8. hartnn

welcome :)