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Study23

  • 3 years ago

Logarithm help - see drawing...

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  1. Study23
    • 3 years ago
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    |dw:1347511210629:dw|

  2. Study23
    • 3 years ago
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    How do I solve that?

  3. Study23
    • 3 years ago
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    Is it like 1/3 or something? Because 2^3 = 8...

  4. anonymous
    • 3 years ago
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    ask yourself what power you would raise the number 8 to in order to get 2 i.e. solve \(8^x=2\) for \(x\)

  5. anonymous
    • 3 years ago
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    yes, it is \(\frac{1}{3}\) because \[8^{\frac{1}{3}}=\sqrt[3]{8}=2\]

  6. hartnn
    • 3 years ago
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    use the property of logarithm: \(\huge log_ba=\frac{log a}{log b}\) yup its 1/3.

  7. Study23
    • 3 years ago
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    Thanks @hartnn & @satellite73!

  8. hartnn
    • 3 years ago
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    welcome :)

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