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do you want a demonstration?

general involving a ,b c and if possible a demonstration also

it seems this method is pretty useful for solving quadratics thats why i am revising it

firstly.... you agree that \[ax^2 + bx + c = 0\]
that's the quadratic equation, yes?

yep

now..divide ALL terms by a...what do you get?

where's the x?

x^2+(b/a)x+(c/a)=0

right

now subtract c/a from both sides

\[x^2+(b/a)x=-c/a\]

good.
now divide b/a by 2..what do you get?

only b/a?

yes... but don't touch the equation yet

just divide b/a by 2

\[(x+b/2a)^2=(4c-b^2)/4a\]

4c+b^2 srry

why is it - b^2

4c+b^2 srry

i see

thx

now take the square root of both sides

do you need further help?

nop gt it

okay then

you can use completing the square method anywhere