A community for students.
Here's the question you clicked on:
 0 viewing
AravindG
 3 years ago
what us completing the square method..i knew it but frgt can anyone help me ?
AravindG
 3 years ago
what us completing the square method..i knew it but frgt can anyone help me ?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you want a demonstration?

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1general involving a ,b c and if possible a demonstration also

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1it seems this method is pretty useful for solving quadratics thats why i am revising it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0firstly.... you agree that \[ax^2 + bx + c = 0\] that's the quadratic equation, yes?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now..divide ALL terms by a...what do you get?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now subtract c/a from both sides

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0good. now divide b/a by 2..what do you get?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes... but don't touch the equation yet

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1\[(x+b/2a)^2=(4cb^2)/4a\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[x^2 + (\frac ba)x + \frac{b^2}{4a^2} = \frac ca + \frac{b^2}{4a^2}\] \[\implies (x + \frac ba)^2 = \frac{b^2  4ac}{4a^2}\] you rushed too fast

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now take the square root of both sides

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you need further help?

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1@lgbasallote can you tell me how we can say that this method will be easier when we have an arbitrary quadratic?i mean is there any relation btw a,b,c so that i can recognise "AHA I CAN USE COMPLETING THE SQUARE HERE INSTEAD OF OTHER METHODS!"

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you can use completing the square method anywhere
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.