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AravindG
 2 years ago
what us completing the square method..i knew it but frgt can anyone help me ?
AravindG
 2 years ago
what us completing the square method..i knew it but frgt can anyone help me ?

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lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.2do you want a demonstration?

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.1general involving a ,b c and if possible a demonstration also

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.1it seems this method is pretty useful for solving quadratics thats why i am revising it

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.2firstly.... you agree that \[ax^2 + bx + c = 0\] that's the quadratic equation, yes?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.2now..divide ALL terms by a...what do you get?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.2now subtract c/a from both sides

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.2good. now divide b/a by 2..what do you get?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.2yes... but don't touch the equation yet

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.2just divide b/a by 2

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.1\[(x+b/2a)^2=(4cb^2)/4a\]

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.2\[x^2 + (\frac ba)x + \frac{b^2}{4a^2} = \frac ca + \frac{b^2}{4a^2}\] \[\implies (x + \frac ba)^2 = \frac{b^2  4ac}{4a^2}\] you rushed too fast

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.2now take the square root of both sides

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.2do you need further help?

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.1@lgbasallote can you tell me how we can say that this method will be easier when we have an arbitrary quadratic?i mean is there any relation btw a,b,c so that i can recognise "AHA I CAN USE COMPLETING THE SQUARE HERE INSTEAD OF OTHER METHODS!"

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.2you can use completing the square method anywhere
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