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rishabh.mission Group Title

Problem... How continuity of a function define or how it existence define ?

  • one year ago
  • one year ago

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  1. zzr0ck3r Group Title
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    the real definition of continuity can be found with google, but i seems one needs some analysis to understand it.

    • one year ago
  2. rishabh.mission Group Title
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    i know the definition but i it is hard to understand ?

    • one year ago
  3. zzr0ck3r Group Title
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    onlyyou can answer that

    • one year ago
  4. zzr0ck3r Group Title
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    this sums it up three conditions: first, f has to be defined at c. Second, the limit on the left hand side of that equation has to exist. Third, the value of this limit must equal f(c).

    • one year ago
  5. rishabh.mission Group Title
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    can u answer how? same is Written on my book but the explanation is poor ?

    • one year ago
  6. zzr0ck3r Group Title
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    do you understand limits?

    • one year ago
  7. zzr0ck3r Group Title
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    if you do then the three conditions I gave you should be able to understand. if not, then just know if you have to lift your pencil to draw the graph, it is NOT continuous

    • one year ago
  8. rishabh.mission Group Title
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    yes right

    • one year ago
  9. rishabh.mission Group Title
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    after that

    • one year ago
  10. zzr0ck3r Group Title
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    ?

    • one year ago
  11. rishabh.mission Group Title
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    bro i know if i lift my pencil to draw the graph then, it is NOT continuous

    • one year ago
  12. zzr0ck3r Group Title
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    yes

    • one year ago
  13. zzr0ck3r Group Title
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    ok man, I dont know what to tell you. Your asking me if you can understand something that you already know. i guess theanswer is no

    • one year ago
  14. rishabh.mission Group Title
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    dude plz understand . can you plz use Qus to define it .but proper qus.

    • one year ago
  15. zzr0ck3r Group Title
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    qus?

    • one year ago
  16. rishabh.mission Group Title
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    question bro.

    • one year ago
  17. rishabh.mission Group Title
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    use this Qus?

    • one year ago
  18. rishabh.mission Group Title
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    show that the function f(x) given by |dw:1347528958353:dw|

    • one year ago
  19. rishabh.mission Group Title
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    in 1st Eq\[x \neq 0\] in 2nd Eq x=0

    • one year ago
  20. zzr0ck3r Group Title
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    you want me to defne something with a question? this is not possible...

    • one year ago
  21. zzr0ck3r Group Title
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    ok so i the first equation at -.0000000000001 and .0000000000001 = the secd eqution at 0

    • one year ago
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