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BIGDOG96

  • 3 years ago

Given: In ∆ACB, c2 = a2 + b2. Prove: ∆ACB is a right angle. Complete the flow chart proof with missing reasons to prove that ∆ACB is a right angle. Which pair of reasons correctly completes this proof? Answers Reason #1 - Transitive Property of Equality Reason #2 - SSS Postulate Reason #1 - Reflexive Property of Equality Reason #2 - SAS Postulate Reason #1 - Transitive Property of Equality Reason #2 - SAS Postulate Reason #1 - Reflexive Property of Equality Reason #2 - SSS Postulate

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  1. BIGDOG96
    • 3 years ago
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  2. BIGDOG96
    • 3 years ago
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  3. ganeshie8
    • 3 years ago
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    f^2 = a^2+b^2 = c^2 => f^2 = c^2 whats above property ?

  4. ganeshie8
    • 3 years ago
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    is it transitive/reflexive ?

  5. BIGDOG96
    • 3 years ago
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    ???

  6. Tahamemon94
    • 3 years ago
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    didnt get either !!!

  7. BIGDOG96
    • 3 years ago
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    I'm not the only one?...good

  8. ganeshie8
    • 3 years ago
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    check this and see if you can tell which property it is, http://www.mathwords.com/e/equation_rules.htm

  9. BIGDOG96
    • 3 years ago
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    Reflexive?

  10. ganeshie8
    • 3 years ago
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    reflexive says, a=a which property is similar to below : f^2 = a^2+b^2 = c^2 => f^2 = c^2

  11. ganeshie8
    • 3 years ago
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    isnt it like, If a = b and b = c then a = c. ?

  12. BIGDOG96
    • 3 years ago
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    Transitive Property

  13. BIGDOG96
    • 3 years ago
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    I should of gone with my gut.

  14. ganeshie8
    • 3 years ago
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    finally ! thats right :)

  15. ganeshie8
    • 3 years ago
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    we need to check what congruence postulate it is

  16. BIGDOG96
    • 3 years ago
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    I think it's SSS.

  17. ganeshie8
    • 3 years ago
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    thats right! we are given two sides are congruent already, and we have just proven the third side f is also congruent. so its SSS you're Awesome :)

  18. BIGDOG96
    • 3 years ago
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    No you are!

  19. ganeshie8
    • 3 years ago
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    lol okiee

  20. BIGDOG96
    • 3 years ago
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    Last question...yay

  21. ganeshie8
    • 3 years ago
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    okay lets do...

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