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anonymous
 3 years ago
Given: In ∆ABC, segment DE is parallel to segment AC.
Prove: BD over BA equals BE over BC
The twocolumn proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally.
Complete the proof by entering the correct statements and reasons.
anonymous
 3 years ago
Given: In ∆ABC, segment DE is parallel to segment AC. Prove: BD over BA equals BE over BC The twocolumn proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally. Complete the proof by entering the correct statements and reasons.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1347551396246:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What are the blanks? If you don't mind me asking.

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.14th row we need to fill

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1so lets see whats happening in the next row  5th one

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1yea in 5th row, we are using AA similarity. which means we need two congruent Angles ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1did u understand 3rd row ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Not really, I'm not good with Postulates.

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1347552555431:dw

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1look at the pix, DE is parallel to AC, its given

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, I understand that.

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1now lets do some imagination

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1think, you slide the side AC up and put it over DE

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1347552973501:dw

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1then, since both lines are parallel, if you shrink AC, A overlaps wid D and C overlaps with E

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1since two sets of corresponding angles are equal, both triangles, small and big ones, are similar

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1347553320251:dw

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1so 4th statement can we have like this : < BED \(\cong\) <BCA by "Corresponding Angles Postulate" ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1347553430140:dw

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1good lets think of last row

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1last row must contain the thing asked for proving

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Prove: BD over BA equals BE over BC

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1yea so lets put the last statement as \( \frac{BD}{BA} = \frac{BE}{BC} \)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1can you think of what will be the Reason/justification ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Um to be honest I have no idea...........Like I said I'm horrible at justifications.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So the answer is BDBA=BEBC "Corresponding sides of similar triangles are proportional"?
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