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BIGDOG96
Group Title
Given: In ∆ABC, segment DE is parallel to segment AC.
Prove: BD over BA equals BE over BC
The twocolumn proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally.
Complete the proof by entering the correct statements and reasons.
 one year ago
 one year ago
BIGDOG96 Group Title
Given: In ∆ABC, segment DE is parallel to segment AC. Prove: BD over BA equals BE over BC The twocolumn proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally. Complete the proof by entering the correct statements and reasons.
 one year ago
 one year ago

This Question is Closed

TheMind Group TitleBest ResponseYou've already chosen the best response.1
dw:1347551396246:dw
 one year ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
What are the blanks? If you don't mind me asking.
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
4th row we need to fill
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
so lets see whats happening in the next row  5th one
 one year ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
4th and 6th
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
yea in 5th row, we are using AA similarity. which means we need two congruent Angles ?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
did u understand 3rd row ?
 one year ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
Not really, I'm not good with Postulates.
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dw:1347552555431:dw
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
look at the pix, DE is parallel to AC, its given
 one year ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
Yes, I understand that.
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
now lets do some imagination
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
think, you slide the side AC up and put it over DE
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dw:1347552973501:dw
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
then, since both lines are parallel, if you shrink AC, A overlaps wid D and C overlaps with E
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
since two sets of corresponding angles are equal, both triangles, small and big ones, are similar
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dw:1347553320251:dw
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
so 4th statement can we have like this : < BED \(\cong\) <BCA by "Corresponding Angles Postulate" ?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dw:1347553430140:dw
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
good lets think of last row
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
last row must contain the thing asked for proving
 one year ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
Prove: BD over BA equals BE over BC
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
yea so lets put the last statement as \( \frac{BD}{BA} = \frac{BE}{BC} \)
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
can you think of what will be the Reason/justification ?
 one year ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
Um to be honest I have no idea...........Like I said I'm horrible at justifications.
 one year ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
So the answer is BDBA=BEBC "Corresponding sides of similar triangles are proportional"?
 one year ago
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