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BIGDOG96
Group Title
Given: In ∆ABC, segment DE is parallel to segment AC.
Prove: BD over BA equals BE over BC
The twocolumn proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally.
Complete the proof by entering the correct statements and reasons.
 2 years ago
 2 years ago
BIGDOG96 Group Title
Given: In ∆ABC, segment DE is parallel to segment AC. Prove: BD over BA equals BE over BC The twocolumn proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally. Complete the proof by entering the correct statements and reasons.
 2 years ago
 2 years ago

This Question is Closed

TheMind Group TitleBest ResponseYou've already chosen the best response.1
dw:1347551396246:dw
 2 years ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
What are the blanks? If you don't mind me asking.
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
4th row we need to fill
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
so lets see whats happening in the next row  5th one
 2 years ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
4th and 6th
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
yea in 5th row, we are using AA similarity. which means we need two congruent Angles ?
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
did u understand 3rd row ?
 2 years ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
Not really, I'm not good with Postulates.
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dw:1347552555431:dw
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
look at the pix, DE is parallel to AC, its given
 2 years ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
Yes, I understand that.
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
now lets do some imagination
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
think, you slide the side AC up and put it over DE
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dw:1347552973501:dw
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
then, since both lines are parallel, if you shrink AC, A overlaps wid D and C overlaps with E
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
since two sets of corresponding angles are equal, both triangles, small and big ones, are similar
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dw:1347553320251:dw
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
so 4th statement can we have like this : < BED \(\cong\) <BCA by "Corresponding Angles Postulate" ?
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dw:1347553430140:dw
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
good lets think of last row
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
last row must contain the thing asked for proving
 2 years ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
Prove: BD over BA equals BE over BC
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
yea so lets put the last statement as \( \frac{BD}{BA} = \frac{BE}{BC} \)
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
can you think of what will be the Reason/justification ?
 2 years ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
Um to be honest I have no idea...........Like I said I'm horrible at justifications.
 2 years ago

BIGDOG96 Group TitleBest ResponseYou've already chosen the best response.0
So the answer is BDBA=BEBC "Corresponding sides of similar triangles are proportional"?
 2 years ago
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