Suppose that for the general population, 1 in
5000 people carries the human immunodeficiency
virus (HIV). A test for the presence of HIV yields
either a positive () or negative () response.
Suppose the test gives the correct answer 99% of
the time. What is P[-|H], the conditional probability
that a person tests negative given that the
person does have the HIV virus? What is P[H|+],
the conditional probability that a randomly chosen
person has the HIV virus given that the person
tests positive?

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@satellite73

P[-|H]= P[- * H] / P[H]
.01/(1/5000)

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