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kpham

  • 3 years ago

evaluate: lim x->2 sqrt (6-x)-2/sqrt (3-x)-1

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  1. kpham
    • 3 years ago
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    valuate: lim x->2 [sqrt (6-x)]-2/[sqrt (3-x)]-1

  2. kpham
    • 3 years ago
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    help me plzz

  3. zzr0ck3r
    • 3 years ago
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    do u know lhopital rule?

  4. kpham
    • 3 years ago
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    whats that

  5. kpham
    • 3 years ago
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    im learning about limits and valuate limit

  6. rainbow22
    • 3 years ago
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    Square top and bottom?

  7. kpham
    • 3 years ago
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    top is sqrt of 6-x only bottom is sqrt of 3-x only

  8. febylailani
    • 3 years ago
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    two sided limit doesnt exist.

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